Thanks for the responses!
I'd forgotten about using the sys module:
import sys
filename = sys.argv[0]
Using "__file__" also works.
Thanks
Scott
On Nov 29, 2004, at 9:37 AM, Scott Frankel wrote:
I'm looking for a way to identify a filename remotely. Put
differently,
is there a way
Scott Frankel wrote:
> I'm looking for a way to identify a filename remotely. Put differently,
> is there a way a file can get its own name from its globals()?
>
> doit.py calls exec() on a second py script, tpairs.py, to obtain a dict of
> the globals in
> tpairs.py. How can I add the filenam
