Ian Kelly gmail.com> writes:
> Depending on your Python version lst is either a range object or a
> list, neither of which is an iterator. If you pass to consume an
> iterable object that is not an iterator, it will implicitly obtain an
> iterator for it, consume from the iterator, and then disc
On Fri, Mar 8, 2013 at 1:28 PM, Skip Montanaro wrote:
> I've never really used itertools before. While trying to figure out
> how to break a list up into equal pieces, I came across the consume
> function in the examples here:
>
> http://docs.python.org/2/library/itertools.html
>
> It seems to me
