On 7.2.2012 16:02, Peter Otten wrote:
Antti J Ylikoski wrote:
On 7.2.2012 14:13, Jean Dupont wrote:
ser2 = serial.Serial(voltport, 2400, 8, serial.PARITY_NONE, 1,
rtscts=0, dsrdtr=0, timeout=15)
In Python, if you want to continue the source line into the next text
line, you must end the line
On 7 feb, 15:04, Heiko Wundram wrote:
> Am 07.02.2012 14:48, schrieb Antti J Ylikoski:
>
> > On 7.2.2012 14:13, Jean Dupont wrote:
> >> ser2 = serial.Serial(voltport, 2400, 8, serial.PARITY_NONE, 1,
> >> rtscts=0, dsrdtr=0, timeout=15)
>
> > In Python, if you want to continue the source line into
Am 07.02.2012 14:48, schrieb Antti J Ylikoski:
On 7.2.2012 14:13, Jean Dupont wrote:
ser2 = serial.Serial(voltport, 2400, 8, serial.PARITY_NONE, 1,
rtscts=0, dsrdtr=0, timeout=15)
In Python, if you want to continue the source line into the next text
line, you must end the line to be continued
Antti J Ylikoski wrote:
> On 7.2.2012 14:13, Jean Dupont wrote:
>> ser2 = serial.Serial(voltport, 2400, 8, serial.PARITY_NONE, 1,
>> rtscts=0, dsrdtr=0, timeout=15)
>
> In Python, if you want to continue the source line into the next text
> line, you must end the line to be continued with a backs
On 7.2.2012 14:13, Jean Dupont wrote:
ser2 = serial.Serial(voltport, 2400, 8, serial.PARITY_NONE, 1,
rtscts=0, dsrdtr=0, timeout=15)
In Python, if you want to continue the source line into the next text
line, you must end the line to be continued with a backslash '\'.
So you should write:
s
On 7 feb, 06:07, Roy Smith wrote:
> In article
> ,
> Jean Dupont wrote:
>
> > I'd like to read in a stream of data which looks like this:
> > the device sends out a byte-string of 11 bytes roughly every second:
>
> > B0B0B0B0B03131B0B50D8A
> > B0B0B0B0B03131B0B50D8A
> > B0B0B031B6313
In article
,
Jean Dupont wrote:
> I'd like to read in a stream of data which looks like this:
> the device sends out a byte-string of 11 bytes roughly every second:
>
> B0B0B0B0B03131B0B50D8A
> B0B0B0B0B03131B0B50D8A
> B0B0B031B63131B0310D8A
> B0B034B3323432B3310D8A
> B0B03