That should have been:
>>> sets.sort(key=len)
>>> reduce(set.intersection, sets)
The only refinement was the pre-sort based on set length.
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[Peter Otten]
> >>> sets = map(set, "abc bcd cde".split())
> >>> reduce(set.intersection, sets)
> set(['c'])
Very nice. Here's a refinement:
>>> sets.sort(key=len)
>>> reduce(set.intersection, sets[1:], sets[0])
set(['c'])
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Suresh Jeevanandam wrote:
> I have a list of sets in variable lsets .
> Now I want to find the intersection of all the sets.
>
> r = lsets[0]
> for s in r[0:]:
> r = r & s
Try to post working examples.
> Is there any other shorter way?
>>> sets = map(set, "abc bcd cde".split())
>>> reduce(
