On Fri, 07 May 2010 18:58:59 +0530 wrote
>mannu jha wrote:
> On Thu, 06 May 2010 18:54:59 +0530 wrote
>
>> mannu jha wrote:
>>
>
>
>> I tried with this:
>>
>
>
>
>
>> for line in open('1.txt'):
>>
>
>
>> columns = line.split()
>>
>
>
>> print column
Dave Angel wrote:
mannu jha
wrote:
I tried with this:
for line in open('1.txt'):
columns = line.split()
print columns[0], columns[1]
if not line: continue
but it is showing error:
nmru...@caf:~> python split.py
24 ALA
Traceback (most recent call last):
File "split.py",
mannu jha wrote:
I tried with this:
for line in open('1.txt'):
columns = line.split()
print columns[0], columns[1]
if not line: continue
but it is showing error:
nmru...@caf:~> python split.py
24 ALA
Traceback (most recent call last):
File "split.py", line 3, in
pri
I tried with this:
for line in open('1.txt'):
columns = line.split()
print columns[0], columns[1]
if not line: continue
but it is showing error:
nmru...@caf:~> python split.py
24 ALA
Traceback (most recent call last):
File "split.py", line 3, in
print columns[0], col
mannu jha wrote:
Hi,
I have few files like this:
24 ALA helix (helix_alpha, helix2)
27 ALA helix (helix_alpha, helix2)
51 ALA helix (helix_alpha, helix4)
58 ALA helix (helix_alpha, helix5)
63 ALA helix (helix_alpha, helix5)
now with this program:
for line in open('1.txt'):
You need to ignore empty lines.
for line in open('1.txt'):
if len(line.strip()) == 0:
continue
columns = line.split()
print columns[0], columns[2]
Cheers,
Xav
On Thu, May 6, 2010 at 6:22 PM, mannu jha wrote:
> Hi,
>
> I have few files like this:
>
> 24 ALA helix (helix_alph
