On Jun 19, 12:32 pm, "Gabriel Genellina" <[EMAIL PROTECTED]>
wrote:
> En Tue, 19 Jun 2007 14:57:10 -0300, <[EMAIL PROTECTED]> escribió:
>
> >> > #win32event.WAIT_TIMEOUT = 2 --- This just makes the loop
> >> > never execute because
> >> > # the WaitFor... part always returns 258
>
>
En Tue, 19 Jun 2007 14:57:10 -0300, <[EMAIL PROTECTED]> escribió:
>> > #win32event.WAIT_TIMEOUT = 2 --- This just makes the loop
>> > never execute because
>> > # the WaitFor... part always returns 258
>>
>> WAIT_TIMEOUT is 258. How do you see it is 2?
>> py> import win32event
>> p
On Jun 19, 10:21 am, "Gabriel Genellina" <[EMAIL PROTECTED]>
wrote:
> En Tue, 19 Jun 2007 03:45:19 -0300, <[EMAIL PROTECTED]> escribió:
>
> > I can't quite figure out where to set the "socket timeout". I tried
> > setting win32event.WAIT_TIMEOUT, but I'm pretty sure that's not the
> > variable you
En Tue, 19 Jun 2007 03:45:19 -0300, <[EMAIL PROTECTED]> escribió:
> I can't quite figure out where to set the "socket timeout". I tried
> setting win32event.WAIT_TIMEOUT, but I'm pretty sure that's not the
> variable you were talking about. I did manage to make it multi-
> threaded by incorpora
On Jun 18, 2:16 am, "Gabriel Genellina" <[EMAIL PROTECTED]>
wrote:
> En Mon, 18 Jun 2007 00:25:25 -0300, <[EMAIL PROTECTED]> escribió:
>
>
>
>
>
> > I'm trying to serve up a simple XMLRPC server as a windows service. I
> > got it to run properly, I'm just not sure how to stop it properly.
> > Most
En Mon, 18 Jun 2007 00:25:25 -0300, <[EMAIL PROTECTED]> escribió:
> I'm trying to serve up a simple XMLRPC server as a windows service. I
> got it to run properly, I'm just not sure how to stop it properly.
> Most of the documentation/examples I found for this was from forums,
> so I'd love some
