On Wed, Jul 29, 2009 at 3:10 PM, Omer Khalid wrote:
> Hi Dave,
>
> Thanks for your reply. I actually didn't cut and paste my code as it was
> dispersed in different places, i typed the logic behind my code in the email
> (and obiviously made some typos, indentations is some thing else) but my
Plea
Omer Khalid wrote:
Hi Dave,
Thanks for your reply. I actually didn't cut and paste my code as it was
dispersed in different places, i typed the logic behind my code in the email
(and obiviously made some typos, indentations is some thing else) but my
real code does not have these problems as my
Omer Khalid wrote:
Hi,
I am having a very strange problem with modifying a variable in a list
in my program. Here is the code:
To me, this sentence clearly implies that the code that follows is the
code that had the problem. Since the posted code cannot run, it clearly
is not. People should
Hi Dave,
Thanks for your reply. I actually didn't cut and paste my code as it was
dispersed in different places, i typed the logic behind my code in the email
(and obiviously made some typos, indentations is some thing else) but my
real code does not have these problems as my application runs fine
Omer Khalid wrote:
Hi,
I am having a very strange problem with modifying a variable in a list in my
program. Here is the code:
# a list that contains dictionary objects
jobs = []
index=5
for each in range(index):
jobs.append({'v':0})
some_function(index):
if jobs[index]['v'] =
Ricardo Aráoz wrote:
MRAB wrote:
Omer Khalid wrote:
Hi,
I am having a very strange problem with modifying a variable in a
list in my program. Here is the code:
# a list that contains dictionary objects
jobs = []
index=5
for each in range(index):
jobs.append({'v':0})
some_function
Omer Khalid wrote:
Hi,
I am having a very strange problem with modifying a variable in a list
in my program. Here is the code:
# a list that contains dictionary objects
jobs = []
index=5
for each in range(index):
jobs.append({'v':0})
some_function(index):
if jobs[index]['v']
Ok, so I found out that even though mylist[] and all objects in it were
fine ie id(mylist[i]) != id(mylist[all others]) what was happening is
that during a reproduction function a shallow copies were being made
making all offspring (genetic algorithm) have different
id(mylist[0..n]), however the ac
Ok, so I found out that even though mylist[] and all objects in it were
fine ie id(mylist[i]) != id(mylist[all others]) what was happening is
that during a reproduction function a shallow copies were being made
making all offspring (genetic algorithm) have different
id(mylist[0..n]), however the ac
Ok, so I found out that even though mylist[] and all objects in it were
fine ie id(mylist[i]) != id(mylist[all others]) what was happening is
that during a reproduction function a shallow copies were being made
making all offspring (genetic algorithm) have different
id(mylist[0..n]), however the ac
Ok, so I found out that even though mylist[] and all objects in it were
fine ie id(mylist[i]) != id(mylist[all others]) what was happening is
that during a reproduction function a shallow copies were being made
making all offspring (genetic algorithm) have different
id(mylist[0..n]), however the ac
Ok, so I found out that even though mylist[] and all objects in it were
fine ie id(mylist[i]) != id(mylist[all others]) what was happening is
that during a reproduction function a shallow copies were being made
making all offspring (genetic algorithm) have different
id(mylist[0..n]), however the ac
[EMAIL PROTECTED] a écrit :
> The Problem (very basic, but strange):
>
> I have a list holding a population of objects, each object has 5 vars
> and appropriate funtions to get or modify the vars.
Which are probably not necessary:
http://dirtsimple.org/2004/12/python-is-not-java.html
(in short:
John Zenger wrote:
> Your list probably contains several references to the same object,
> instead of several different objects. This happens often when you use a
> technique like:
>
> list = [ object ] * 100
>
> ..because although this does make copies when "object" is an integer, it
> just makes
John Zenger wrote:
> Your list probably contains several references to the same object,
> instead of several different objects. This happens often when you use a
> technique like:
>
> list = [ object ] * 100
This is most likely what's going on. To the OP: please post the
relevant code, including
On Fri, 07 Apr 2006 21:18:12 -0400, John Zenger wrote:
> Your list probably contains several references to the same object,
> instead of several different objects. This happens often when you use a
> technique like:
>
> list = [ object ] * 100
>
> ..because although this does make copies when
Your list probably contains several references to the same object,
instead of several different objects. This happens often when you use a
technique like:
list = [ object ] * 100
..because although this does make copies when "object" is an integer, it
just makes references in other cases.
[E
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