On Sep 28, 7:37 pm, Scott wrote:
> On Sep 28, 2:00 pm, Dave Angel wrote:
>
>
>
> > Scott wrote:
> > > Thank you fine folks for getting back with your answers!
>
> > > So down the road I do dictname[line42].append("new stuff"). (or [var]
> > > if I'm looping through the dict)
>
> > Nope, you still
Hendrik van Rooyen wrote:
> On Monday, 28 September 2009 18:54:09 Scott wrote:
>> I am new to Python but I have studied hard and written a fairly big
>> (to me) script/program. I have solved all of my problems by Googling
>> but this one has got me stumped.
>>
>> I want to check a string for a sub
On Monday, 28 September 2009 18:54:09 Scott wrote:
> I am new to Python but I have studied hard and written a fairly big
> (to me) script/program. I have solved all of my problems by Googling
> but this one has got me stumped.
>
> I want to check a string for a substring and if it exists I want to
On Sep 28, 2:00 pm, Dave Angel wrote:
> Scott wrote:
> > Thank you fine folks for getting back with your answers!
>
> > So down the road I do dictname[line42].append("new stuff"). (or [var]
> > if I'm looping through the dict)
>
> Nope, you still haven't gotten it. Of course, I really don't know
Scott wrote:
Thank you fine folks for getting back with your answers!
So down the road I do dictname[line42].append("new stuff"). (or [var]
if I'm looping through the dict)
Nope, you still haven't gotten it. Of course, I really don't know where
you're going wrong, since you didn't use the
> That should actually be dictname["line42"].append("new stuff"). Notice
> the quotes around line42.
>
> Good luck! Python is a fine language, I hope you like it.
>
> ~Ethan~
Doh. I sent it before my type, fail, fix cycle had taken place.
Got it.
Thanks again all!
--
http://mail.python.org/mai
Scott wrote:
Thank you fine folks for getting back with your answers!
So down the road I do dictname[line42].append("new stuff").
The keys are strings, so
dictname['line42'].append("new stuff")
or
for key in dictname.keys():
...
dictname[key]
tjr
--
http://mail.python.org/mailman/
Scott wrote:
Thank you fine folks for getting back with your answers!
So down the road I do dictname[line42].append("new stuff"). (or [var]
if I'm looping through the dict)
This is cool and should do the trick!
-Scott Freemire
disclosure - Ok, I'm new to *any* language. I've been teaching myse
2009/9/28 Scott :
> Thank you fine folks for getting back with your answers!
>
> So down the road I do dictname[line42].append("new stuff"). (or [var]
> if I'm looping through the dict)
>
> This is cool and should do the trick!
>
> -Scott Freemire
> disclosure - Ok, I'm new to *any* language. I've
Thank you fine folks for getting back with your answers!
So down the road I do dictname[line42].append("new stuff"). (or [var]
if I'm looping through the dict)
This is cool and should do the trick!
-Scott Freemire
disclosure - Ok, I'm new to *any* language. I've been teaching myself
for about 3
Scott wrote:
I am new to Python but I have studied hard and written a fairly big
(to me) script/program. I have solved all of my problems by Googling
but this one has got me stumped.
I want to check a string for a substring and if it exists I want to
create a new, empty list using that substring
Scott wrote:
> for X in open("file1"):
> Do a test.
> If true:
> Y = re.split(" ", X)
> Z = Y[0] # This is a string, maybe it is "Line42"
> Z = [] # This doesn't work, I want a new, empty
> list created called Line42 not Z.
>
> Is there any w
2009/9/28 Scott :
> I am new to Python but I have studied hard and written a fairly big
> (to me) script/program. I have solved all of my problems by Googling
> but this one has got me stumped.
>
> I want to check a string for a substring and if it exists I want to
> create a new, empty list using
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