On Apr 25, 2:55 pm, sdistefano wrote:
> I have the following issue:
>
> My program runs a thread called the MainThread, that loops trough a
> number of URLs and decides when it's the right time for one to be
> fetched. Once a URL has to be fetched, it's added to a Queue object,
> where the Fetchi
mk wrote:
Hello everyone,
I wrote "concurrent ssh" client using Paramiko, available here:
http://python.domeny.com/cssh.py
This program has a function for concurrent remote file/dir copying
(class SSHThread, method 'sendfile'). One thread per host specified is
started for copying (with a wo
Tried that on Python 2.5 on Windows and it worked.
John Nagle
Abandoned wrote:
> Hi..
> I want to threading but i have a interesting error..
> ==
> class SelectAll(threading.Thread):
>def __init__(self, name):
> threading.Thread.__init
Abandoned schrieb:
> Hi..
> I want to threading but i have a interesting error..
> ==
> class SelectAll(threading.Thread):
>def __init__(self, name):
> threading.Thread.__init__(self)
> self.name = name #kelime
>
>def run(self):
>
>
> self.result=.
In message <[EMAIL PROTECTED]>, Philip
Zigoris wrote:
> ... and the server
> would go into a state where the master thread repeatedly polled the
> socket and printed an error.
Is that because it cannot create a new socket to accept the connection on?
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> Here the error message:
Exception in thread Thread-1:
> Traceback (most recent call last):
> File "C:\Program Files\Python\lib\threading.py", line 442, in
> __bootstrap
> self.run()
> File "G:\Robot teleskop\VRT\test\test2.py", line 25, in run
> Document.OpenFile('F:/Images/VRT
Thank You, but now it cannot open a file, but it should work...
Here the error message:
>>> Exception in thread Thread-1:
Traceback (most recent call last):
File "C:\Program Files\Python\lib\threading.py", line 442, in __bootstrap
self.run()
File "G:\Robot teleskop\VRT\test\test2.py", line
Aleksandar Cikota wrote:
> How to integrate the Code-part in the main programm, so that the
> mainprogramm works?
>
> Code:
>
> import win32com.client
> import time
> import os
> import threading
>
> Document = win32com.client.Dispatch('MaxIm.Document')
> Application = win32com.client.Dispatch(
On Wed, 22 Dec 2004 12:55:46 +, Alan Kennedy <[EMAIL PROTECTED]> wrote:
> [Norbert]
> > i am experimenting with threads and get puzzling results.
> > Consider the following example:
> > #
> > import threading, time
> >
> > def threadfunction():
> > print "threadfunction:
Steve Holden wrote:
> Well, I don't believe there's any guarantee that a thread will get run
> preference over its
> starter - they're both threads, after all. Try putting a sleep after
> th.start() and before the
> print statement and you should see that the "worker" thread runs while the
>
Thanks Alan,
i hoped it would be something trivial :)
Norbert
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Thanks a lot, Steve, for your fast reply.
But the behaviour is the same if 'threadfunction' sleeps longer than
just 1 second. 'threadfunction' is of course a dummy to show the
problem, imagine a longrunning background-task.
If you are right, the question remains 'How can I assure that the
starting
[Norbert]
> i am experimenting with threads and get puzzling results.
> Consider the following example:
> #
> import threading, time
>
> def threadfunction():
> print "threadfunction: entered"
> x = 10
> while x < 40:
> time.sleep(1) # time unit is seconds
>
Norbert wrote:
Hello *,
i am experimenting with threads and get puzzling results.
Consider the following example:
#
import threading, time
def threadfunction():
.print "threadfunction: entered"
.x = 10
.while x < 40:
.time.sleep(1) # time unit is seconds
On Fri, 10 Dec 2004 00:12:16 GMT, Steven Bethard
<[EMAIL PROTECTED]> wrote:
I think if you change the call to look like:
threading.Thread(target=run, args=(os.path.join('c:\\', path),)).start()
oh i see now. thanks
s='sdgdfgdfg'
s == (s)
True
s == (s,)
False
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Egor Bolonev wrote:
hi all
my program terminates with error i dont know why it tells 'TypeError:
run() takes exactly 1 argument (10 given)'
[snip]
threading.Thread(target = run, args = (os.path.join('c:\\',
path))).start()
I believe the args argument to threading.Thread is supposed to b
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