Il Mon, 24 Mar 2008 15:05:38 -0700, Julien ha scritto:
...
>
> I'll try to explain a bit more what I'm after, and hopefully that will
> be clearer. In fact, what I'm trying to do is to "hijack" (I'm making up
> the term) a function:
>
> def hijacker(arg):
> if I_feel_its_necessary:
>
On Mar 24, 10:05 pm, Julien <[EMAIL PROTECTED]> wrote:
> Hi all, and thanks a lot for your answers!
>
> I'll try to explain a bit more what I'm after, and hopefully that will
> be clearer. In fact, what I'm trying to do is to "hijack" (I'm making
> up the term) a function:
>
> def hijacker(arg):
>
On Mar 25, 9:05 am, Julien <[EMAIL PROTECTED]> wrote:
> Hi all, and thanks a lot for your answers!
>
> I'll try to explain a bit more what I'm after, and hopefully that will
> be clearer. In fact, what I'm trying to do is to "hijack" (I'm making
> up the term) a function:
>
> def hijacker(arg):
>
Hi all, and thanks a lot for your answers!
I'll try to explain a bit more what I'm after, and hopefully that will
be clearer. In fact, what I'm trying to do is to "hijack" (I'm making
up the term) a function:
def hijacker(arg):
if I_feel_its_necessary:
hijack_caller_function_and_make_
On Mar 24, 9:48 am, Jason <[EMAIL PROTECTED]> wrote:
> On Mar 24, 5:21 am, Julien <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
> > Hello all,
>
> > I would like to do something like:
>
> > def called(arg)
> > if arg==True:
> > !!magic!!caller.return 1
>
> > def caller(arg)
> > called(arg)
>
On Mar 24, 5:21 am, Julien <[EMAIL PROTECTED]> wrote:
> Hello all,
>
> I would like to do something like:
>
> def called(arg)
> if arg==True:
> !!magic!!caller.return 1
>
> def caller(arg)
> called(arg)
> return 2
>
> Here, the fake !!!magic!!! represents a statement (which I ig
On Mon, 24 Mar 2008 04:21:29 -0700, Julien wrote:
> Hello all,
>
> I would like to do something like:
>
> def called(arg)
> if arg==True:
> !!magic!!caller.return 1
Instead of writing "if arg==True", or "if (arg==True)==True", or even
"if ((arg==True)==True)==True", you should just
