I could indeed have addressed this problem with a list comprehension.
It escaped me at the time because the larger problem I was trying to
solve included removing data from a dictionary:
months =
sorted(list(dataDict.keys())) #Sort
months in ascending order
Le 10/02/12 21:48, Thomas Philips a écrit :
Thanks for the insight. I saw the behavious as soon as I extended x
with a bunch of 0's
x = list(range(10))
x.extend([0]*10)
x
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9,
On Sat, Feb 11, 2012 at 7:04 AM, Thomas Philips wrote:
> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
for i in x:
> if i % 2 == 0:
> x.remove(i)
Just a quickie, is there a reason you can't use a list comprehension?
x = [i for i in x if i % 2]
ChrisA
--
http://mail.python.org/mailm
Thanks for the insight. I saw the behavious as soon as I extended x
with a bunch of 0's
>>> x = list(range(10))
>>> x.extend([0]*10)
>>> x
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
>>> for i in reversed(x):
if i % 2 == 0:
x.remove(i)
>>> x
[1, 3, 5, 7, 9
On 10/02/2012 20:04, Thomas Philips wrote:
In the past, when deleting items from a list, I looped through the
list in reverse to avoid accidentally deleting items I wanted to keep.
I tried something different today, and, to my surprise, was able to
delete items correctly, regardless of the direct
On Fri, Feb 10, 2012 at 1:04 PM, Thomas Philips wrote:
> In the past, when deleting items from a list, I looped through the
> list in reverse to avoid accidentally deleting items I wanted to keep.
> I tried something different today, and, to my surprise, was able to
> delete items correctly, regar
On Mon, 20 Apr 2009 20:09:12 -0700, Ross wrote:
> Is there a quick way to simultaneously pop multiple items from a list?
> For instance if i had the list a = [1,2,3,4,5,6,7] and I wanted to
> return every odd index into a new list, my output would be new_list =
> [2,4,6] or similarly if I wanted t
