On Apr 11, 1:13 pm, [EMAIL PROTECTED] wrote:
> Hi folks,
>
> The first line in the file I am examining will be a number followed by
> more whitespace. Looks like I cannot split by whitespace?
> but I get 'cannot open
> file' when i try to read from an archive..
...and that led you to conclude tha
En Fri, 13 Apr 2007 08:59:30 -0300, <[EMAIL PROTECTED]> escribió:
> That works fine if I am using the interpreter, but I get 'cannot open
> file' when i try to read from an archive..
> Does that make sense? Sorry, this is my 2nd python script.
Try a small, failing example and post the code and th
On Apr 11, 4:20 pm, "Gabriel Genellina" <[EMAIL PROTECTED]>
wrote:
> En Wed, 11 Apr 2007 17:15:48 -0300, <[EMAIL PROTECTED]> escribió:
>
> > The file contents have leading whitespace, then a number:
> > 123456 \n
> > I expect to return '123456'
>
> And nothing following the number?
>
> p
En Wed, 11 Apr 2007 17:15:48 -0300, <[EMAIL PROTECTED]> escribió:
> The file contents have leading whitespace, then a number:
> 123456 \n
> I expect to return '123456'
And nothing following the number?
py> line = " 123456 \n"
py> print line.strip()
123456
--
Gabriel Genell
On Apr 11, 4:10 pm, "Gabriel Genellina" <[EMAIL PROTECTED]>
wrote:
> En Wed, 11 Apr 2007 16:13:42 -0300, <[EMAIL PROTECTED]> escribió:
>
>
>
>
>
> > Hi folks,
> > I am trying to read the first occurence of non-whitespace in a file,
> > within a zipfile. Here is my code:
>
> > zipnames = glob.glob("
En Wed, 11 Apr 2007 16:13:42 -0300, <[EMAIL PROTECTED]> escribió:
> Hi folks,
> I am trying to read the first occurence of non-whitespace in a file,
> within a zipfile. Here is my code:
>
> zipnames = glob.glob("*")
> for zipname in zipnames:
> z = zipfile.ZipFile(zipname, "r")
> for filename
[EMAIL PROTECTED] wrote:
> Hi folks,
> I am trying to read the first occurence of non-whitespace in a file,
> within a zipfile. Here is my code:
>
> zipnames = glob.glob("*")
> for zipname in zipnames:
> z = zipfile.ZipFile(zipname, "r")
> for filename in z.namelist():
> count = len(z.read
