[EMAIL PROTECTED] wrote:
> Actually that's what I tried to do, for example:
> outputString = myString.encode('iso-8859-1','ignore')
>
> However, I always get such messages (the character, that's causing problems
> varies, but its always higher than 127 ofc...)
>
> 'ascii' codec can't decode byte
<[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Would that mean that the string "myString" is an ascii-string or what?
It would mean it was a byte encoded string already, yes. When you try to
encode it, Python tries to coerce it to Unicode and it's equivalent to:
myString.decode(
here's still the message about the
'ascii' codec...
Would that mean that the string "myString" is an ascii-string or what?
-Original Message-
From: Marc 'BlackJack' Rintsch [mailto:[EMAIL PROTECTED]
Sent: Donnerstag, 20. März 2008 15:24
To: python-list
On Thu, 20 Mar 2008 13:03:17 +, Dominique.Holzwarth wrote:
> The output of the transformation (a big string containg the whole file)
> contains a so called 'paragraph separator' (unicode: 2029). If I want to
> pring that string (file) to the std out or a file object then I get a
> "UnicodeErro
