Re: Odd behaviour of regexp module

To possibly clearify what the others have said, group() is the same as saying group(0). Group is, if I recall correctly, supposed to return the n-th subpattern from the regular expression (subpatterns, as you know, being indicated by parenthises). Hope that helps :) -Wes -- http://mail.python.or

Re: Odd behaviour of regexp module

Why doesn't group have an argument? group() or group(0) returns what the pattern matched, not what it returns. -- http://mail.python.org/mailman/listinfo/python-list

Re: Odd behaviour of regexp module

Hi David, b.group() is equivalent to b.group(0), the entire RE match. (^(.*?)\.) will give you 'dfsf.' for that input string. What you want is b.group(1), the subgroup you're looking for inside the main RE. (.*?) which gives you 'dfsf', which is what you're looking for. Cheers,