On 01/12/2015 08:49 PM, Steven D'Aprano wrote:
> On Mon, 12 Jan 2015 12:40:13 -0800, Ethan Furman wrote:
>>
>> [...] class name lookup skips nonlocal namespaces.
>
> Actually, no it doesn't.
> [...]
> The "problem" is that *functions* lookup don't include the class body in
> their scope.
Ah, t
On Mon, 12 Jan 2015 12:40:13 -0800, Ethan Furman wrote:
> On 01/12/2015 12:25 PM, John Ladasky wrote:
>> d = {0:"a", 1:"b", 2:"c", 3:"d"}
>> e = [d[x] for x in (0,2)]
>>
>> class Foo:
>> f = {0:"a", 1:"b", 2:"c", 3:"d"}
>> print(f)
>> g = [f[x] for x in (0,2)]
>
> In Foo 'f' is part
On Tue, Jan 13, 2015 at 7:25 AM, John Ladasky
wrote:
> When I am working inside the class namespace, the print function call on line
> 8 recognizes the name f and prints the dictionary bound to that name.
>
> However, the LIST COMPREHENSION defined inside the class namespace generates
> a NameEr
On Monday, January 12, 2015 at 12:41:30 PM UTC-8, Ethan Furman wrote:
> In Foo 'f' is part of an unnamed namespace; the list comp 'g' has its own
> namespace, effectively making be a nonlocal;
> class name lookup skips nonlocal namespaces.
>
> Workaround: use an actual for loop.
Thanks, Ethan.
Following up to myself: I finally did the right keyword search, and found a
relevant article:
http://stackoverflow.com/questions/13905741/accessing-class-variables-from-a-list-comprehension-in-the-class-definition
Maybe I HAVE tried to define a list comprehension inside a class definition
befor
On 01/12/2015 12:25 PM, John Ladasky wrote:
> d = {0:"a", 1:"b", 2:"c", 3:"d"}
> e = [d[x] for x in (0,2)]
>
> class Foo:
> f = {0:"a", 1:"b", 2:"c", 3:"d"}
> print(f)
> g = [f[x] for x in (0,2)]
In Foo 'f' is part of an unnamed namespace; the list comp 'g' has its own
namespace, eff
