Mike Meyer wrote:
>Or - and much safer when dealing with floating point numbers - iterate
>over integers and generate your float values:
>for j in range(1, 9):
> i = j * .25
> print "%9.2f" % i
I agree with this suggestion. As an historical aside, Fortran had loops
with floating point variab
Mike Meyer wrote:
> Or - and much safer when dealing with floating point numbers - iterate
> over integers and generate your float values:
>
> for j in range(1, 9):
> i = j * .25
> print "%9.2f" % i
There's a glitch there, though - should be range(1, 10).
Reinhold
PS: I'm wondering whe
"drife" <[EMAIL PROTECTED]> writes:
> Hello,
>
> Making the transition from Perl to Python, and have a
> question about constructing a loop that uses an iterator
> of type float. How does one do this in Python?
>
> In Perl this construct quite easy:
>
> for (my $i=0.25; $i<=2.25; $i+=0.25) {
> pri
Mark McEahern wrote:
drife wrote:
Hello,
Making the transition from Perl to Python, and have a
question about constructing a loop that uses an iterator
of type float. How does one do this in Python?
Use a generator:
>>> def iterfloat(start, stop, inc):
... f = start
... while f <= stop:
drife wrote:
> Hello,
>
> Making the transition from Perl to Python, and have a
> question about constructing a loop that uses an iterator
> of type float. How does one do this in Python?
>
> In Perl this construct quite easy:
>
> for (my $i=0.25; $i<=2.25; $i+=0.25) {
> printf "%9.2f\n", $i;
>
drife wrote:
Hello,
Making the transition from Perl to Python, and have a
question about constructing a loop that uses an iterator
of type float. How does one do this in Python?
Use a generator:
>>> def iterfloat(start, stop, inc):
... f = start
... while f <= stop:
... yield
