> Here's a tricky case that doesn't show up in your example:
> In each case above, the directory names are distinct.
> how about:
>['/desk', '/desk/ethanallen', '/desk/ikea',
> '/desktop', /desktop/pc', '/desktop/mac']
>Should the answer be ['/desk'] or ['/desk', '/desktop'] ?
Hi Scott
good po
Nico Grubert wrote:
Dear Python developers... I have the following (sorted) list
I want to remove all paths x from the list if there is a path y in the
list which is part of x so y.startswith(x) is true.
The list I want to have is:
['/notebook', '/desktop', '/server/hp/proliant']
Any ide
On Apr 1, 3:57 am, Nico Grubert wrote:
> Dear Python developers
>
> I have the following (sorted) list.
> ['/notebook',
> '/notebook/mac',
> '/notebook/mac/macbook',
> '/notebook/mac/macbookpro',
> '/notebook/pc',
> '/notebook/pc/lenovo',
> '/notebook/pc/hp',
> '/notebook/pc/sony',
>
Sure, generators rock! :-)
2009/4/1 andrew cooke :
> Nico Grubert wrote:
>>> May be not so much pythonic, but works
>>>
>>> for i in range(len(q)):
>>> for x in q[i:]:
>>> if x.startswith(q[i]) and x!=q[i]:
>>> q.remove(x)
>>
>> ...but works fine. Thanks, Eugene.
>> Also th
Nico Grubert wrote:
>> May be not so much pythonic, but works
>>
>> for i in range(len(q)):
>> for x in q[i:]:
>>if x.startswith(q[i]) and x!=q[i]:
>>q.remove(x)
>
> ...but works fine. Thanks, Eugene.
> Also thanks to Andrew. Your example works fine, too. Thanks to remind me
May be not so much pythonic, but works
for i in range(len(q)):
for x in q[i:]:
if x.startswith(q[i]) and x!=q[i]:
q.remove(x)
...but works fine. Thanks, Eugene.
Also thanks to Andrew. Your example works fine, too. Thanks to remind me
of the 'yield' statement! ;-)
Regard
You could use the followingm, where the_list is your list. (I'm new to
python so there might be a better way):
toremove = []
for x in the_list:
for y in the_list:
if y.startswith(x) and y != x:
toremove.append(y)
difference = filter(lambda x:x not
>>> def filter(values):
... last = None
... for value in values:
... if last is None or not value.startswith(last):
... yield value
... last = value
...
>>> for x in filter(['/notebook', ]):
... print(x)
...
/notebook
/desktop
/server/hp/proliant
andrew
Nico Grubert wr
