Sick Monkey escribió:
> I ran into another slight problem. And I attempted to fix it, but have
> not been able to do so yet. If a filename does not contain a space,
> then this method works like a charm. But if there is a space then the
> code throws a nasty error.
Ok, the issue is that sub
On May 31, 2007, at 8:08 PM, Sick Monkey wrote:
I ran into another slight problem. And I attempted to fix it, but
have not been able to do so yet. If a filename does not contain a
space, then this method works like a charm. But if there is a
space then the code throws a nasty error.
i
I ran into another slight problem. And I attempted to fix it, but have not
been able to do so yet. If a filename does not contain a space, then this
method works like a charm. But if there is a space then the code throws a
nasty error.
import os
import subprocess
from os import *
imagefile = "
Sick Monkey wrote:
> When I run the following command:
> [EMAIL PROTECTED] david.huggins]# identify -format %w
> '/someDIR/images/david.huggins/100_0264.JPG'
>From Python interpreter:
>>> cmd = "identify -format %w test.jpg"
>>> p = subprocess.Popen(cmd.split(), stdout=subprocess.PIPE,
>>> stde
On May 30, 2007, at 11:00 PM, Sick Monkey wrote:
When I run the following command:
[EMAIL PROTECTED] david.huggins]# identify -format %w '/someDIR/
images/david.huggins/100_0264.JPG'
I get the following result
2304
However, when I try to set this value to a variable, ie
