chovd...@gmail.com writes:
> Hi friends
>
> help me with the following code. Im able to execute the code but getting
> wrong output
>
> def sequence_b(N):
> N = 10
> result = 0
> for k in xrange (1,N):
> result += ((-1) ** (k+1))/2*k-1
> print result
> print sequenc
On 2013-11-06, Denis McMahon wrote:
> On Wed, 06 Nov 2013 00:35:56 +0200, Nick the Gr33k wrote:
>
>> Now i realizes i just cannot store lists into it's columns because it
>> does not support a collection datatype.
>
> All databases support storing of collections, but *NOT THE WAY YOU WANT
> TO DO
On Wed, Nov 6, 2013 at 3:49 AM, Mark Lawrence wrote:
> On 06/11/2013 01:14, Nick the Gr33k wrote:
>>
>>
>> How, do i i proceed?
>
>
> If at first you don't succeed, keep asking on comp.lang.python until someone
> gives me the completely bodged solution that I keep asking for even if it's
> complet
On 06/11/2013 01:14, Nick the Gr33k wrote:
How, do i i proceed?
If at first you don't succeed, keep asking on comp.lang.python until
someone gives me the completely bodged solution that I keep asking for
even if it's complete nonsense.
--
Python is the second best programming language in t
Op 05-11-13 22:26, Nick the Gr33k schreef:
> I know i'm close to solution, i can feel it but i have some issues.
> The code we arr discussing is the following:
No you are not. You are just doing random changes, without any
understanding. If you had followed my suggestion and actually
read the doc
On Tue, 5 Nov 2013 17:51:00 -0800 (PST), chovd...@gmail.com wrote:
result += ((-1) ** (k+1))/2*k-1
One of two things are happening here. Maybe both.
You're using Python 2.x (and should havesaid so) where integer
division is truncated.
You're missing around some part of the intende
On Tue, 05 Nov 2013 17:51:00 -0800, chovdary wrote:
> Hi friends
>
> help me with the following code. Im able to execute the code but getting
> wrong output
[snip code]
You have this critical expression in your code:
result += ((-1) ** (k+1))/2*k-1
It looks to me like you are using Python 2
On 06/11/2013 01:51, chovd...@gmail.com wrote:
Hi friends
help me with the following code. Im able to execute the code but getting wrong
output
def sequence_b(N):
N = 10
result = 0
for k in xrange (1,N):
result += ((-1) ** (k+1))/2*k-1
print result
print sequ
Denis McMahon writes:
> You have been told several times by several people how to do this
> properly. You insist on using your bodged up solution instead. OK, we'll
> all try and help you bodge up a solution[…]
Why? No-one here is obligated to help with implementing a solution we
agree is bad.
Στις 6/11/2013 12:54 πμ, ο/η John Gordon έγραψε:
The code i provided only worked once before it failed and managed to
store this:
counterID,host,refs,city,userOS,browser,visits,hits,download
-
1, 176-92-96-218.adsl.cyta.gr, Euro
On Wed, 06 Nov 2013 00:35:56 +0200, Nick the Gr33k wrote:
> Now i realizes i just cannot store lists into it's columns because it
> does not support a collection datatype.
All databases support storing of collections, but *NOT THE WAY YOU WANT
TO DO IT*
You refuse to do it the proper way, so yo
On 05/11/2013 22:31, Cameron Simpson wrote:
On 05Nov2013 20:09, Nikos wrote:
O even better an rdbms than allows complex data such as tuples,
lists, dicts to be saved into the db as they are so i dont have to
cobvet back and forth each time.
If you're just using the db for storage or adhoc and
There is also the shelve module.
It uses pickle to marshal a Python object, then stores it in a file
under a key.
Sample code from the module documentation:
import shelve
d = shelve.open(filename) # open -- file may get suffix added by
low-level library
d[key] = data # store data at key
On 05Nov2013 20:09, Nikos wrote:
> O even better an rdbms than allows complex data such as tuples,
> lists, dicts to be saved into the db as they are so i dont have to
> cobvet back and forth each time.
If you're just using the db for storage or adhoc and arbitrary
python objects (and not queryin
In Nick the Gr33k
writes:
> The code i provided only worked once before it failed and managed to
> store this:
>
> counterID,host,refs,city,userOS,browser,visits,hits,download
> -
> 1, 176-92-96-218.adsl.cyta.gr, Europe/Athens,
On 05/11/2013 22:28, Nick the Gr33k wrote:
Στις 6/11/2013 12:06 πμ, ο/η John Gordon έγραψε:
In Nick the Gr33k
writes:
# fetch those columns that act as lists but are stored as
strings
cur.execute('''SELECT refs, visits, downloads FROM visitors
WHERE
counterID = %s and host =
Στις 6/11/2013 12:15 πμ, ο/η Piet van Oostrum έγραψε:
Nick the Gr33k writes:
IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
ALL I WANT IT TO DO IS JUST
1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
2. CONVERT LONG STRINGS TO LISTS
3. ADD SOME CURRENT VALUES TO THOSE L
Στις 6/11/2013 12:06 πμ, ο/η John Gordon έγραψε:
In Nick the Gr33k
writes:
# fetch those columns that act as lists but are stored as
strings
cur.execute('''SELECT refs, visits, downloads FROM visitors
WHERE
counterID = %s and host = %s''', (cID, host) )
Nick the Gr33k writes:
>
> IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
>
> ALL I WANT IT TO DO IS JUST
>
> 1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
> 2. CONVERT LONG STRINGS TO LISTS
> 3. ADD SOME CURRENT VALUES TO THOSE LISTS
> 4. CONVERT FROM LISTS TO LONG STRINGS
In Nick the Gr33k
writes:
> # fetch those columns that act as lists but are stored as
> strings
> cur.execute('''SELECT refs, visits, downloads FROM visitors
> WHERE
> counterID = %s and host = %s''', (cID, host) )
> data = cur.fetchone()
>
On Wed, Nov 6, 2013 at 8:17 AM, Mark Lawrence wrote:
> I've taken a different approach. I've put the contract out to tender and
> hereby give you the winners
> http://www.mudefordwoodcommunitycentre.co.uk/playgroup-and-tiny-tots/
Sounds good! But I don't see a list of their technologies - do they
On 05/11/2013 21:17, Mark Lawrence wrote:
On 05/11/2013 20:19, John Gordon wrote:
In Nick the Gr33k
writes:
IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
ALL I WANT IT TO DO IS JUST
1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
2. CONVERT LONG STRINGS TO LISTS
3
Στις 5/11/2013 10:19 μμ, ο/η John Gordon έγραψε:
In Nick the Gr33k
writes:
IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
ALL I WANT IT TO DO IS JUST
1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
2. CONVERT LONG STRINGS TO LISTS
3. ADD SOME CURRENT VALUES TO THOS
On 05/11/2013 20:19, John Gordon wrote:
In Nick the Gr33k
writes:
IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
ALL I WANT IT TO DO IS JUST
1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
2. CONVERT LONG STRINGS TO LISTS
3. ADD SOME CURRENT VALUES TO THOSE LISTS
4
In Nick the Gr33k
writes:
> IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
> ALL I WANT IT TO DO IS JUST
> 1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
> 2. CONVERT LONG STRINGS TO LISTS
> 3. ADD SOME CURRENT VALUES TO THOSE LISTS
> 4. CONVERT FROM LISTS TO LONG STRING
On Tue, 05 Nov 2013 20:09:42 +0200, Nick the Gr33k wrote:
> Denis, i have already provided my code trying to do what i need and i
> need some commendation on how to make it work.
Nick, you're obviously trying to code way above your abilities.
If you want me to write your code, you will have to p
On Tue, Nov 5, 2013 at 1:11 PM, Tobiah wrote:
> All this problem arises because MySQL's hasn't got a datatype able to store
> an array of elements, a list.
>
> Um, yes it does. It's called a table.
> --
> https://mail.python.org/mailman/listinfo/python-list
Perhaps we are splitting hairs, but a
All this problem arises because MySQL's hasn't got a datatype able to store an
array of elements, a list.
Um, yes it does. It's called a table.
--
https://mail.python.org/mailman/listinfo/python-list
Στις 5/11/2013 8:02 μμ, ο/η Denis McMahon έγραψε:
On Tue, 05 Nov 2013 19:06:25 +0200, Nick the Gr33k wrote:
IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
Try starting with something simple. The following is a step by step guide
to working out how you need to do this. Follow a
On Tue, 05 Nov 2013 19:06:25 +0200, Nick the Gr33k wrote:
> IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
Try starting with something simple. The following is a step by step guide
to working out how you need to do this. Follow all the steps. Do not skip
any steps. Each stage bu
Στις 5/11/2013 7:41 μμ, ο/η Steven D'Aprano έγραψε:
On Tue, 05 Nov 2013 19:06:25 +0200, Nick the Gr33k wrote:
ALL I WANT IT TO DO IS JUST
1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS 2. CONVERT LONG
STRINGS TO LISTS
3. ADD SOME CURRENT VALUES TO THOSE LISTS 4. CONVERT FROM LISTS TO LON
Op 05-11-13 18:41, Steven D'Aprano schreef:
> On Tue, 05 Nov 2013 19:06:25 +0200, Nick the Gr33k wrote:
>
>> ALL I WANT IT TO DO IS JUST
>>
>> 1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS 2. CONVERT LONG
>> STRINGS TO LISTS
>> 3. ADD SOME CURRENT VALUES TO THOSE LISTS 4. CONVERT FROM LISTS
On Tue, 05 Nov 2013 19:06:25 +0200, Nick the Gr33k wrote:
> ALL I WANT IT TO DO IS JUST
>
> 1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS 2. CONVERT LONG
> STRINGS TO LISTS
> 3. ADD SOME CURRENT VALUES TO THOSE LISTS 4. CONVERT FROM LISTS TO LONG
> STRINGS SO I CAN STORE SUCCESSFULLY LIST
EVERYHTIGN I TRIED FAILED.
Maybe try some of the advice you have been given instead?
--
https://mail.python.org/mailman/listinfo/python-list
> =
>
> IAM STRUGGLING WITH IT 2 DAYS NOW AND I CANNOT GET IT TO WORK.
>
> ALL I WANT IT TO DO IS JUST
>
> 1. RETRIEVE 3 COLUMNS THAT CONSIST OF 3 LONG STRINGS
> 2. CONVERT LONG STRINGS TO LISTS
> 3. ADD SOME CURRENT VALUES TO THOSE LISTS
> 4. CONVERT
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