On Oct 25, 4:33 am, Kelson Zawack wrote:
> The example I have in mind is list like [2,2,2,2,2,2,1,3,3,3,3] where
> you want to loop until you see not a 2 and then you want to loop until
> you see not a 3. In this situation you cannot use a for loop as
> follows:
>
> foo_list_iter = iter([2,2,2,2,
Kelson Zawack writes:
> The example I have in mind is list like [2,2,2,2,2,2,1,3,3,3,3] where
> you want to loop until you see not a 2 and then you want to loop until
> you see not a 3.
"loop until you see not a 2" - you mean yield 2s as long as there are 2s
to be consumed?
"loop until you see
Kelson Zawack writes:
> Iterators however are a different beast, they are returned by the
> thing they are iterating over and thus any special cases can be
> covered by writing a specific implementation for the iterable in
> question. This sort of functionality is possible to implement,
> becaus
Kelson Zawack writes:
> The example I have in mind is list like [2,2,2,2,2,2,1,3,3,3,3]
> where you want to loop until you see not a 2 and then you want to
> loop until you see not a 3. In this situation you cannot use a for
> loop as follows:
...
> because it will eat the 1 and not allow the sec
Kelson Zawack, 25.10.2010 12:33:
The example I have in mind is list like [2,2,2,2,2,2,1,3,3,3,3] where
you want to loop until you see not a 2 and then you want to loop until
you see not a 3. In this situation you cannot use a for loop as
follows:
foo_list_iter = iter([2,2,2,2,2,2,1,3,3,3,3])
fo
The example I have in mind is list like [2,2,2,2,2,2,1,3,3,3,3] where
you want to loop until you see not a 2 and then you want to loop until
you see not a 3. In this situation you cannot use a for loop as
follows:
foo_list_iter = iter([2,2,2,2,2,2,1,3,3,3,3])
for foo_item in foo_list_iter:
if
Hello,
On Thu, Oct 21, 2010 at 12:26:50PM +, Steven
D'Aprano wrote:
> I know what you're thinking: "it's easy to cache
> the next result, and return it on the next
> call". But iterators can also be dependent on
> the time that they are called, like in this
> example:
>
> def evening_time():
Kelson Zawack writes:
> Since an iterator having an end is not actually an exceptional case...
There's no requirement on iterators to be finite, so in a sense it is.
In general it may be impractical to know whether an iterator has reached
the end without calling next().
--
http://mail.python
On Thu, 21 Oct 2010 19:08:00 +0800, Kelson Zawack wrote:
> I have been programing in python for a while now and by in large love
> it. One thing I don't love though is that as far as I know iterators
> have no has_next type functionality. As a result if I want to iterate
> until an element that
On Thu, 21 Oct 2010 09:36:41 -0200, Felipe Bastos Nunes wrote:
> Looking in the documentation, only the StopIteration raises. I'd like a
> hasNext() too. I'll see if it is easy to implement,
Iterators can be unpredictable. In general, you can't tell whether an
iterator is finished or not until
Kelson Zawack writes:
> […] if I want to iterate until an element that might or might not be
> present is found I either wrap the while loop in a try block or break
> out of a for loop.
I'm not sure what exception you would catch, but that could be a good
solution.
The general solution would b
Looking in the documentation, only the StopIteration raises. I'd like
a hasNext() too. I'll see if it is easy to implement, but maybe it'sn
ot yet there coz for does the work greatly.
2010/10/21, Kelson Zawack :
> I have been programing in python for a while now and by in large love
> it. One thi
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