HMS Surprise <[EMAIL PROTECTED]> wrote:
...
> Why is apply deprecated?
Because it does exacly the same job as just calling the function with
*a/**k, and there should preferably be only one obvious way to perform a
given task (this guiding principle leads to simplicity in the language,
and is co
On Mar 16, 6:44 pm, James Stroud <[EMAIL PROTECTED]> wrote:
> HMS Surprise wrote:
> > Seems to me that one should be able to put the names of several
> > functions in a list and then have the list executed. But it seems the
> > output of the functions is hidden, only their return value is visible.
HMS Surprise wrote:
> Seems to me that one should be able to put the names of several
> functions in a list and then have the list executed. But it seems the
> output of the functions is hidden, only their return value is visible.
> Is this because the list execution is another scope?
>
> Thanx,
>
Hi!
Your code run OK for me.
But, if you want "time-lag" (sorry for my english) execution, you can
try this:
def a():
print "this is a"
def b():
print "this is b"
lst = [a, b]
[f() for f in lst]
--
@-salutations
Michel Claveau
--
http://mail.python.org/mailman/listinfo/py
On Mar 16, 3:59 pm, "7stud" <[EMAIL PROTECTED]> wrote:
> lst = [a, b]
>
> The () symbol causes the named function to execute, and a function
> call in the code is always replaced by the function's return value.
Try this:
--
def a():
print "this is a"
def b():
print "this is b
lst = [a, b]
The () symbol causes the named function to execute, and a function
call in the code is always replaced by the function's return value.
--
http://mail.python.org/mailman/listinfo/python-list
