italy wrote:
> Why doesn't this statement execute in Python:
>
> 1 == not 0
>
> I get a syntax error, but I don't know why.
>
> Thanks,
> Adam Roan
Of course, you would normally want to use != to see if something is not
equal to something else.
1 != 0
True
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In <[EMAIL PROTECTED]>, italy wrote:
> Why doesn't this statement execute in Python:
>
> 1 == not 0
>
> I get a syntax error, but I don't know why.
`==` has a higher precedence than `not` so Python interprets it as::
(1 == not) 0
This works::
>>> 1 == (not 0)
True
Ciao,
Marc
"not" has a lower priority than non-Boolean operators, so not a == b is
interpreted as not (a == b), and a == not b is a syntax error.
http://docs.python.org/lib/boolean.html
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> Why doesn't this statement execute in Python:
>
> 1 == not 0
>
> I get a syntax error, but I don't know why.
This does: 1 == (not 0)
I presume Python treats it like
1 (== not) 0
Which is a SyntaxError
greets,
Marek
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italy wrote:
Why doesn't this statement execute in Python:
1 == not 0
I get a syntax error, but I don't know why.
Because == has higher precedence than 'not', so you are asking for
(1 == not) 0
Try
>>> 1 == (not 0)
True
Kent
Thanks,
Adam Roan
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