Sayth Renshaw wrote:
> def output_data(s):
> serie = fibo(input_length)
> x = []
> y = []
>
> for num1, num2 in pairwise(serie):
> y.append( num2 / num1)
It looks like y contains unique values. In that case replace
> for item in y:
> x.append(y.index(item
On Wednesday, 21 August 2019 03:16:01 UTC+10, Ian wrote:
> Or use the "pairwise" recipe from the itertools docs:
>
> from itertools import tee
>
> def pairwise(iterable):
> "s -> (s0,s1), (s1,s2), (s2, s3), ..."
> a, b = tee(iterable)
> next(b, None)
> return zip(a, b)
>
> for n
Or use the "pairwise" recipe from the itertools docs:
from itertools import tee
def pairwise(iterable):
"s -> (s0,s1), (s1,s2), (s2, s3), ..."
a, b = tee(iterable)
next(b, None)
return zip(a, b)
for num1, num2 in pairwise(a):
print(num1, num2)
On Tue, Aug 20, 2019 at 7:42 AM
Sayth Renshaw wrote:
> I want to do basic math with a list.
>
> a = [1, 2, 3, 4, 5, 6, 7, 8]
>
> for idx, num in enumerate(a):
> print(idx, num)
>
> This works, but say I want to print the item value
> at the next index as well as the current.
>
> for idx, num in enumerate(a):
>
> print(n
On 20/08/2019 13:00, Sayth Renshaw wrote:
> Hi
>
> I want to do basic math with a list.
>
>
> for idx, num in enumerate(a):
> print(idx, num)
>
> This works, but say I want to print the item value at the next index as well
> as the current.
>
> for idx, num in enumerate(a):
> print(
On 2019-08-20 2:00 PM, Sayth Renshaw wrote:
Hi
I want to do basic math with a list.
a = [1, 2, 3, 4, 5, 6, 7, 8]
for idx, num in enumerate(a):
print(idx, num)
This works, but say I want to print the item value at the next index as well as
the current.
for idx, num in enumerate(a):
