On 9 fév, 04:02, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote:
> En Thu, 08 Feb 2007 23:32:50 -0300, Sick Monkey <[EMAIL PROTECTED]>
> escribió:
>
> > db = {'[EMAIL PROTECTED]':'none', '[EMAIL PROTECTED]':'none',
> > '[EMAIL PROTECTED]':'none',
> > '[EMAIL PROTECTED]':'none',}
>
> > And I want to
At Friday 9/2/2007 00:50, you wrote:
Hey Gabriel,
Please keep posting on the list - you'll reach a whole lot of people there...
Thanks again for the help... but im still having some issues.
For some reason the "domsrch.search(key)" is pointing to a memory
reference... so when
En Thu, 08 Feb 2007 23:32:50 -0300, Sick Monkey <[EMAIL PROTECTED]>
escribió:
> db = {'[EMAIL PROTECTED]':'none', '[EMAIL PROTECTED]':'none',
> '[EMAIL PROTECTED]':'none',
> '[EMAIL PROTECTED]':'none',}
>
> And I want to pull out all of the "gmail.com" addresses.. How would I do
> this?
>
> N
"Nick Vatamaniuc" <[EMAIL PROTECTED]> writes:
> if l[-1].setdefault(a+c, x+e) l[-1][a+c]=x+e
Thanks for the answer. I will try it.
--
Brian (remove the sport for mail)
http://www.et.web.mek.dtu.dk/Staff/be/be.html
Rugbyklubben Speed Scandinavian Open 7s Rugby http://www.rkspeed.dk
--
http:
"Justin Azoff" <[EMAIL PROTECTED]> writes:
> last[keytotal] = min(last.get(keytotal), valtotal)
> comes close to working - it would if you were doing max.
Thanks, I think this would help.
--
Brian (remove the sport for mail)
http://www.et.web.mek.dtu.dk/Staff/be/be.html
Rugbyklubben Speed Scan
John Machin <[EMAIL PROTECTED]> writes:
> 2. Put spaces around operators -- in general, RTFStyleGuide
>http://www.python.org/dev/peps/pep-0008
I din't know it. Thanks.
> Only you know what *really* meaningful names you should be using.
I have better names in my running code.
> mykey = a +
On 18/07/2006 9:51 PM, Brian Elmegaard wrote:
> Brian Elmegaard <[EMAIL PROTECTED]> writes:
>
> At least it was clumsy to post a wrong example.
> This shows what = find clumsy.
>
> c=1
> x=2
>
> l=list()
> l.append(dict())
> l[0][5]=0
>
> l.append(dict())
>
> for a, e in l[-2].iteritems():
> #
Brian Elmegaard wrote:
> for a, e in l[-2].iteritems():
> # Can this be written better?
> if a+c in l[-1]:
> if l[-1][a+c] l[-1][a+c]=x+e
> else:
> l[-1][a+c]=x+e
> #
I'd start with something like
for a, e in l[-2].iteritems():
keytotal = a
Brian,
You can try the setdefault method of the dictionary.
For a dictionary D the setdefault work like this:
D.setdefault(k, defvalue). If k not in D then D[k] is set to defvalue
and defvalue is returned.
For example:
In [1]: d={}
In [2]: d.setdefault(1,5)
Out[2]:5
In [3]: d
Out[3]:{1: 5}
In y
Brian Elmegaard <[EMAIL PROTECTED]> writes:
At least it was clumsy to post a wrong example.
This shows what = find clumsy.
c=1
x=2
l=list()
l.append(dict())
l[0][5]=0
l.append(dict())
for a, e in l[-2].iteritems():
# Can this be written better?
if a+c in l[-1]:
if l[-1][a+c
A simple way to get individual values for the distribution is:
d = {}
for i in range( 0, 1000):
j = random.randrange( 0, 100)
if d.has_key(j):
d[j] += 1
else:
d[j] = 1
keys = d.keys()
keys.sort()
for key in keys:
print key, ":", "*" * d[key]
--
http://mail.pytho
hawkesed wrote:
Actually,
I think I got it now. Here is what I did:
for num in alist:
... if adict.has_key(num):
... x = adict.get(num)
... x = x + 1
... adict.update({num:x})
A simpler way to do this last line is
adict[num] = x
... else:
...
hawkesed said unto the world upon 2005-04-21 20:28:
Actually,
I think I got it now. Here is what I did:
for num in alist:
... if adict.has_key(num):
... x = adict.get(num)
... x = x + 1
... adict.update({num:x})
... else:
... adict.updat
Actually,
I think I got it now. Here is what I did:
>>> for num in alist:
... if adict.has_key(num):
... x = adict.get(num)
... x = x + 1
... adict.update({num:x})
... else:
... adict.update({num:1})
...
>>> adict
{128: 2, 129: 2, 132: 1, 15
Steve,
thanks for the input. That is actually what I am trying to do, but I
don't know the syntax for this in python. For example here is a list I
want to work with as input:
[101, 66, 75, 107, 108, 101, 106, 98, 111, 88, 119, 93, 115, 95, 114,
95, 118, 109, 85, 75, 88, 97, 53, 78, 98, 91, 115, 77
Here is an example of the input list:
[101, 66, 75, 107, 108, 101, 106, 98, 111, 88, 119, 93, 115, 95, 114,
95, 118, 109, 85, 75, 88, 97, 53, 78, 98, 91, 115, 77, 107, 153, 108,
101]
Here is the code I am working on now:
>>> for num in alist:
... if adict.has_key(num):
... x = adic
"hawkesed" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
> I am semi new to Python. Here is my problem : I have a list of 100
> random integers. I want to be able to construct a histogram out of the
> data. So I want to know how many 70's, 71's, etc. I can't figure out
> how
Simon Brunning wrote:
On 21 Apr 2005 02:47:42 -0700, hawkesed <[EMAIL PROTECTED]> wrote:
I am semi new to Python. Here is my problem : I have a list of 100
random integers. I want to be able to construct a histogram out of the
data. So I want to know how many 70's, 71's, etc. I can't figure out
ho
On 21 Apr 2005 02:47:42 -0700, hawkesed <[EMAIL PROTECTED]> wrote:
> I am semi new to Python. Here is my problem : I have a list of 100
> random integers. I want to be able to construct a histogram out of the
> data. So I want to know how many 70's, 71's, etc. I can't figure out
> how to do this.
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