On Jun 2, 8:36 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote:
> Still nitpicking: using a generator expression in this case has no
> advantage. The first thing that str.join does is to create a list out of
> its argument (unless it is already a list or a tuple). In fact, a list
> comprehension
En Mon, 02 Jun 2008 18:56:08 -0300, jay graves <[EMAIL PROTECTED]>
escribió:
On Jun 2, 4:02 pm, Larry Bates <[EMAIL PROTECTED]> wrote:
I think what you want is:
def write_err(*args):
from sys import stderr
stderr.write("\n".join([str(o) for o in args]))
Slight nitpick. If you are
On Jun 2, 2:56 pm, jay graves <[EMAIL PROTECTED]> wrote:
> On Jun 2, 4:02 pm, Larry Bates <[EMAIL PROTECTED]> wrote:
>
> > I think what you want is:
> > def write_err(*args):
> > from sys import stderr
> > stderr.write("\n".join([str(o) for o in args]))
>
> Slight nitpick. If you are usi
bukzor wrote:
I have this function:
def write_err(obj):
from sys import stderr
stderr.write(str(obj)+"\n")
and I'd like to rewrite it to take a variable number of objects.
Something like this:
def write_err(*objs):
from sys import stderr
stderr.write(" ".join(objs)+"\n")
b
On Jun 2, 4:02 pm, Larry Bates <[EMAIL PROTECTED]> wrote:
> I think what you want is:
> def write_err(*args):
> from sys import stderr
> stderr.write("\n".join([str(o) for o in args]))
Slight nitpick. If you are using version >= 2.4 you could use a
generator expression instead of a list
bukzor wrote:
I have this function:
def write_err(obj):
from sys import stderr
stderr.write(str(obj)+"\n")
and I'd like to rewrite it to take a variable number of objects.
Something like this:
def write_err(*objs):
from sys import stderr
stderr.write(" ".join(objs)+"\n")
b
