On 10 March 2016 at 13:02, Peter Otten <__pete...@web.de> wrote:
> Heli wrote:
>
>> I need to loop over a numpy array and then do the following search. The
>> following is taking almost 60(s) for an array (npArray1 and npArray2 in
>> the example below) with around 300K values.
>>
>>
>> for id in np
problem is infact not related to numpy at all. the complexity of your
algorithm is O(len(npArray1) * len(npArray2))
which means the number of computations that you are doing is in the range
of 10**10,
if the absolute difference between the maximum element and minimum element
is less than 10**6, y
> From: sjeik_ap...@hotmail.com
> To: heml...@gmail.com; python-list@python.org
> Subject: RE: looping and searching in numpy array
> Date: Sun, 13 Mar 2016 13:51:23 +
>
> Hi, I suppose you have seen this already (in particular the first link):
> http://nump
> Date: Thu, 10 Mar 2016 08:48:48 -0800
> Subject: Re: looping and searching in numpy array
> From: heml...@gmail.com
> To: python-list@python.org
>
> On Thursday, March 10, 2016 at 2:02:57 PM UTC+1, Peter Otten wrote:
> > Heli wrote:
> >
> > > Dear
On Thursday, March 10, 2016 at 5:49:07 PM UTC+1, Heli wrote:
> On Thursday, March 10, 2016 at 2:02:57 PM UTC+1, Peter Otten wrote:
> > Heli wrote:
> >
> > > Dear all,
> > >
> > > I need to loop over a numpy array and then do the following search. The
> > > following is taking almost 60(s) for an
On Thursday, March 10, 2016 at 2:02:57 PM UTC+1, Peter Otten wrote:
> Heli wrote:
>
> > Dear all,
> >
> > I need to loop over a numpy array and then do the following search. The
> > following is taking almost 60(s) for an array (npArray1 and npArray2 in
> > the example below) with around 300K val
On 10/03/2016 11:43, Heli wrote:
Dear all,
I need to loop over a numpy array and then do the following search. The
following is taking almost 60(s) for an array (npArray1 and npArray2 in the
example below) with around 300K values.
for id in np.nditer(npArray1):
newId=(np.where(npArr
Heli wrote:
> Dear all,
>
> I need to loop over a numpy array and then do the following search. The
> following is taking almost 60(s) for an array (npArray1 and npArray2 in
> the example below) with around 300K values.
>
>
> for id in np.nditer(npArray1):
>
>newId=(n
