not exactly for the homework, but as my starting point of learning
thank you so much.
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> From: denismfmcma...@gmail.com
[...]
>> Dear all who involved with responding to my question - Thank you so much
>> for your nice code which really helped me.
>
> Hold on a sec? Someone posted code that gave the correct answer to a
> homework question?
>
>
On Thu, 23 May 2013 07:17:58 -0700, Keira Wilson wrote:
> Dear all who involved with responding to my question - Thank you so much
> for your nice code which really helped me.
Hold on a sec? Someone posted code that gave the correct answer to a
homework question?
--
Denis McMahon, denismfmcma.
Dear all who involved with responding to my question - Thank you so much for
your nice code which really helped me.
--
http://mail.python.org/mailman/listinfo/python-list
On Thu, May 23, 2013 at 10:37 AM, Carlos Nepomuceno
wrote:
>
>> From: oscar.j.benja...@gmail.com
>> Date: Thu, 23 May 2013 01:34:37 +0100
>> Subject: Re: file I/O and arithmetic calculation
>> To: carlosnepomuc...@outlook.com
&g
On 23 May 2013 04:15, Carlos Nepomuceno wrote:
> The last line of my noob piece can be improved. So this is it:
Most of it can be improved.
> filenames = ['1.txt', '2.txt', '3.txt', '4.txt', '5.txt']
> contents = [[[int(z) for z in y.split(',')] for y in open(x).read().split()]
> for x in file
The last line of my noob piece can be improved. So this is it:
### 1strow_average.py ###
#Assuming you have CSV (comma separated values) files such as:
#1.txt = '0,1,2,3,4,5,6,7,8,9\n' \
# '10,11,12,13,14,15,16,17,18,19\n' \
# '20,21,22,23,24,25,26,27,28,29\n' ...
#
# Usage: contents
> From: oscar.j.benja...@gmail.com
> Date: Thu, 23 May 2013 01:34:37 +0100
> Subject: Re: file I/O and arithmetic calculation
> To: carlosnepomuc...@outlook.com
> CC: python-list@python.org
>
> On 23 May 2013 00:49, Carlos Nepomuceno
On 23 May 2013 00:49, Carlos Nepomuceno wrote:
>
> The code is pretty obvious to me, I mean there's no obfuscation at all.
I honestly can't tell if you're joking.
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> From: denismfmcma...@gmail.com
[...]
>
> import re
> def v(s):
> l=len(s)
> t=0.
> for i in range(l):
> t=t+(abs(ord(s[i]))*1.)
> return t/(l*1.)
> for n in range(5):
> m="c:/test/"+str(n+1)+".txt"
> f=open(m,"r")
> d=[]
> t=0.
> for l in range(10):
> d=d+
On Thu, 23 May 2013 01:13:19 +0900, Keira Wilson wrote:
> I would appreciate if someone could write a simple python code for the
> purpose below:
Didn't have your data, so couldn't verify it completely, but try this:
import re
def v(s):
l=len(s)
t=0.
for i in range(l):
t=t+(abs(ord(s[i]))*1
># contents[3][4][5] : 6th column of 5th row of file '4.txt'
BTW, it should read
# contents[3][4][5] : 6th value of 5th row of file '4.txt'
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> From: oscar.j.benja...@gmail.com
[...]
>
> Do you find this code easy to read? I wouldn't write something like
> this and I certainly wouldn't use it when explaining something to a
> beginner.
>
> Rather than repeated list comprehensions you should conside
On 22 May 2013 22:05, Carlos Nepomuceno wrote:
>
> filenames = ['1.txt', '2.txt', '3.txt', '4.txt', '5.txt']
> contents = [[[int(z) for z in y.split(',')] for y in open(x).read().split()]
> for x in filenames]
> s1c = [sum([r[0] for r in f]) for f in contents]
> a1r = [sum(f[0])/float(len(f[0]
Funny! I made a lot of assumptions regarding your requirements specification.
Let me know if it isn't what you need:
### 1strow_average.py ###
#Assuming you have CSV (comma separated values) files such as:
#1.txt = '0,1,2,3,4,5,6,7,8,9\n' \
# '10,11,12,13,14,15,16,17,18,19\n' \
# '2
On 22/05/2013 17:13, Keira Wilson wrote:
Dear all,
I would appreciate if someone could write a simple python code for the
purpose below:
I have five text files each of 10 columns by 10 rows as follows:
|file_one= 'C:/test/1.txt'
file_two= 'C:/test/2.txt'
. . .
file_five= 'C:/test/5.txt'|
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