On 2021-03-06 8:21 AM, Frank Millman wrote:
Hi all
This is purely academic, but I would like to understand the following -
>>>
>>> a = [('x', 'y')]
>>>
>>> s = []
>>> for b, c in a:
... s.append((b, c))
...
>>> s
[('x', 'y')]
This is what I expected.
>>>
>>> s = []
>>> s.append(((
On Sat, Mar 06, 2021 at 08:21:47AM +0200, Frank Millman wrote:
> [...]
> I understand the concept that a generator does not return a value until you
> call next() on it, but I have not grasped the essential difference between
> the above two constructions.
>
> TIA for any insights.
>
> Frank Mill
>>>
>>> s = []
>>> s.append(((b, c) for b, c in a))
>>> s
[ at 0x019FC3F863C0>]
>>>
TIA for any insights.
Replace "append" above with "extend" and observe the results. Then
ponder the difference between append and extend. I suspect that the
heart of your confusion actua
Hi all
This is purely academic, but I would like to understand the following -
>>>
>>> a = [('x', 'y')]
>>>
>>> s = []
>>> for b, c in a:
... s.append((b, c))
...
>>> s
[('x', 'y')]
This is what I expected.
>>>
>>> s = []
>>> s.append(((b, c) for b, c in a))
>>> s
[ at 0x019FC3F863C0>]
> Cameron Pulsford (CP) wrote:
>CP> I read it on the haskell site in their sieves/prime wheel section,
>CP> I guess I misunderstood something. (east to do over there...) I did
>CP> verify it against established list of primes and other generators
>CP> I've written that use more normal methods
On Jul 13, 1:17 pm, Cameron Pulsford
wrote:
> I read it on the haskell site in their sieves/prime wheel section, I
> guess I misunderstood something. (east to do over there...) I did
> verify it against established list of primes and other generators I've
> written that use more normal metho
I read it on the haskell site in their sieves/prime wheel section, I
guess I misunderstood something. (east to do over there...) I did
verify it against established list of primes and other generators I've
written that use more normal methods, but I only hand verified it.
It is at least int
On Sun, Jul 12, 2009 at 9:24 PM, Cameron
Pulsford wrote:
> As far as the primes generator, it does not generate any non-primes. All
> primes (except 2, 3 and 5) are in the form (6*x + 1, 6*x + 5) where is x is
> [1, 2, ..., n]. The only time it doesn't generate a prime is when x + (1 or
> 5) % 5 ==
On Jul 13, 11:24 am, Cameron Pulsford
wrote:
> As far as the primes generator, it does not generate any non-primes.
> All primes (except 2, 3 and 5) are in the form (6*x + 1, 6*x + 5)
> where is x is [1, 2, ..., n]. The only time it doesn't generate a
> prime is when x + (1 or 5) % 5 == 0.
itertools.chain() did it, thanks!
As far as the primes generator, it does not generate any non-primes.
All primes (except 2, 3 and 5) are in the form (6*x + 1, 6*x + 5)
where is x is [1, 2, ..., n]. The only time it doesn't generate a
prime is when x + (1 or 5) % 5 == 0. Which is what that
Cameron Pulsford wrote:
When you start a new thread, you should start a new thread and not
piggyback on an existing thread.
--
http://mail.python.org/mailman/listinfo/python-list
> Cameron Pulsford (CP) wrote:
>CP> Hey everyone, I have this small piece of code that simply finds the
>CP> factors of a number.
Others have already given you advice to add the [2, 3, 5] to the
iterator (of which the primes.extend([2,3,5]) will not work). Please
allow me to make some other
2009/7/12 Cameron Pulsford :
> My question is, is it possible to combine those two loops? The primes
> generator I wrote finds all primes up to n, except for 2, 3 and 5, so I must
> check those explicitly. Is there anyway to concatenate the hard coded list
> of [2,3,5] and the generator I wrote so
On Jul 12, 2:11 pm, Cameron Pulsford
wrote:
> Hey everyone, I have this small piece of code that simply finds the
> factors of a number.
>
> import sys
>
> def factor(n):
> primes = (6*i+j for i in xrange(1, n) for j in [1, 5] if (i+j)%5 !
> = 0)
>
> factors = []
>
> for i in [2,
Hey everyone, I have this small piece of code that simply finds the
factors of a number.
import sys
def factor(n):
primes = (6*i+j for i in xrange(1, n) for j in [1, 5] if (i+j)%5 !
= 0)
factors = []
for i in [2, 3, 5]:
while n % i == 0:
n /= i
f
Thanks for reply :)
I'm little sceptic about this code:
>>> a = gen1()
>>> a.gi_frame.f_code.co_name
'gen1'
will it be compatible with Python 2.3, 2.4, 2.5+ and future versions?
Seems very internal and subject of future change.
A.
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<[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
> Is there a way for created generators to determine what function
> created them?
> Like for objects and classes function 'isinstance',
>
> e.g.:
>
> def gen1( ):
>yield 1
>
> a = gen1( )
>
> if isinstance( a, gen1 ) == True: #n
Hi,
Is there a way for created generators to determine what function
created them?
Like for objects and classes function 'isinstance',
e.g.:
def gen1( ):
yield 1
a = gen1( )
if isinstance( a, gen1 ) == True: #not functional.
...
Thanks for reply,
Andrej
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