On 23Aug2015 09:28, Laura Creighton wrote:
In a message of Sat, 22 Aug 2015 06:53:21 -, ali ranjbar writes:
I have python version 2.4.3
Which version of PIL is appropriate for me and how can I add it to my systems?
If you really have python 2.4.3 then you badly need a newer Python.
If h
In a message of Sat, 22 Aug 2015 06:53:21 -, ali ranjbar writes:
>hi dear friend
>
>I have python version 2.4.3
>
>Which version of PIL is appropriate for me and how can I add it to my systems?
>
>Regards
>
>--
>https://mail.python.org/mailman/listinfo/python-list
If you really have python 2.
hi dear friend
I have python version 2.4.3
Which version of PIL is appropriate for me and how can I add it to my systems?
Regards
--
https://mail.python.org/mailman/listinfo/python-list
> I tried these this:
>
> string = string.replace('\s*Field One\s*
> %FieldOneValue%\s*', '')
>
>
> But this doesn't work. The doco for Python's regex suggests that \s
> should match any whitespace including newlines which is what I
> wanted,
from http://docs.python.org/lib/module-re.html
"
[EMAIL PROTECTED] a écrit :
> I am doing a string.replace in a simple table generation app I wrote,
> and I can't figure out how to match whitespace with /s,
Hahem... Where did you get the idea that str.replace would work with
regexps ?
"""
replace(...)
S.replace (old, new[, count]) -> st
I am doing a string.replace in a simple table generation app I wrote,
and I can't figure out how to match whitespace with /s, so I thought
I would see if osmeone where would be kind enough to tell me what I am
getting wrong.
This works:
string = string.replace('\n Field One
\n %Field