In <0c642381-4dd2-48c5-bb22-b38f2d5b2...@googlegroups.com>
paul.garcia2...@gmail.com writes:
> Write a program which prints the sum of numbers from 1 to 101
> (1 and 101 are included) that are divisible by 5 (Use while loop)
> x=0
> count=0
> while x<=100:
> if x%5==0:
> count=count+
On 29/11/2016 23:58, paul.garcia2...@gmail.com wrote:
Write a program which prints the sum of numbers from 1 to 101 ( 1 and 101 are
included) that are divisible by 5 (Use while loop)
This is the code:
x=0
count=0
while x<=100:
if x%5==0:
count=count+x
x=x+1
print(count)
This
On 2016-11-29 23:58, paul.garcia2...@gmail.com wrote:
Write a program which prints the sum of numbers from 1 to 101 ( 1 and 101 are
included) that are divisible by 5 (Use while loop)
This is the code:
x=0
count=0
while x<=100:
if x%5==0:
count=count+x
x=x+1
print(count)
Quest
Write a program which prints the sum of numbers from 1 to 101 ( 1 and 101 are
included) that are divisible by 5 (Use while loop)
This is the code:
x=0
count=0
while x<=100:
if x%5==0:
count=count+x
x=x+1
print(count)
Question: How does python know what count means ? I
On Tue, 01 Jul 2014 14:40:18 +0200, Peter Otten wrote:
> What I'm trying to tell you: you need to put in some work to identify
> the culprit...
His next question was "how do I read a range from excel, please give me
an example"
I gave him an example of using google to search for solutions to hi
Jaydeep Patil wrote:
> Dear Peter,
> I have tested code written by you. But still it is taking same time.
Too bad ;(
If you run the equivalent loop written in Basic from within Excel -- is that
faster?
If you run the loop in Python with some made-up data instead of that fetched
from Excel --
On Monday, 30 June 2014 18:16:21 UTC+5:30, Peter Otten wrote:
> Jaydeep Patil wrote:
>
>
>
> > I have did excel automation using python.
>
> > In my code I am creating python dictionaries for different three columns
>
> > data at a time.There are are many rows above 4000. Lets have look in be
marco.naw...@colosso.nl wrote:
In the past I even dumped an EXCEL sheet as a
CSV file
That's probably the only way you'll speed things up
significantly. In my experience, accessing Excel via
COM is abysmally slow no matter how you go about it.
--
Greg
--
https://mail.python.org/mailman/listinf
On Monday, June 30, 2014 1:32:23 PM UTC+2, Jaydeep Patil wrote:
> I have did excel automation using python.
>
> In my code I am creating python dictionaries for different three columns data
> at a time.There are are many rows above 4000. Lets have look in below
> function. Why it is taking too m
Jaydeep Patil wrote:
> I have did excel automation using python.
> In my code I am creating python dictionaries for different three columns
> data at a time.There are are many rows above 4000. Lets have look in below
> function. Why it is taking too much time?
>
> Code:
>
> def transientTestDict
I have did excel automation using python.
In my code I am creating python dictionaries for different three columns data
at a time.There are are many rows above 4000. Lets have look in below function.
Why it is taking too much time?
Code:
def transientTestDict(self,ws,startrow,startcol):
Am 01.03.2013 17:28, schrieb Isaac Won:
What I really want to get from this code is m1 as I told. For this
purpose, for instance, values of fpsd upto second loop and that from
third loop should be same, but they are not. Actually it is my main
question.
You are not helping yourself...
In any
Thank you Ulich for reply,
What I really want to get from this code is m1 as I told. For this purpose, for
instance, values of fpsd upto second loop and that from third loop should be
same, but they are not. Actually it is my main question.
Thank you,
Isaac
On Friday, March 1, 2013 6:00:42 AM UTC
On Friday, March 1, 2013 7:41:05 AM UTC-6, Chris Angelico wrote:
> On Fri, Mar 1, 2013 at 7:59 PM, Isaac Won wrote:
>
> > while c <24:
>
> > for columns in ( raw.strip().split() for raw in f ):
>
> > while d <335:
>
>
>
> Note your indentation levels: the code does not agree
Thank you, Chris.
I just want to acculate value from y repeatedly.
If y = 1,2,3...10, just have a [1,2,3...10] at onece.
On Friday, March 1, 2013 7:41:05 AM UTC-6, Chris Angelico wrote:
> On Fri, Mar 1, 2013 at 7:59 PM, Isaac Won wrote:
>
> > while c <24:
>
> > for columns in ( raw.strip
On Fri, Mar 1, 2013 at 7:59 PM, Isaac Won wrote:
> while c <24:
> for columns in ( raw.strip().split() for raw in f ):
> while d <335:
Note your indentation levels: the code does not agree with your
subject line. The third loop is not actually inside your second.
Should it be?
Ch
On Fri, Mar 1, 2013 at 7:00 AM, Ulrich Eckhardt <
ulrich.eckha...@dominolaser.com> wrote:
> Am 01.03.2013 09:59, schrieb Isaac Won:
>
> try to make my triple nested loop working. My code would be:
>> c = 4
>>
> [...]
>
> while c <24:
>> c = c + 1
>>
>
> This is bad style and you shouldn
Am 01.03.2013 09:59, schrieb Isaac Won:
try to make my triple nested loop working. My code would be:
c = 4
[...]
while c <24:
c = c + 1
This is bad style and you shouldn't do that in python. The question that
comes up for me is whether something else is modifying "c" in that loop,
try to make my triple nested loop working. My code would be:
c = 4
y1 = []
m1 = []
std1 = []
while c <24:
c = c + 1
a = []
f.seek(0,0)
for columns in ( raw.strip().split() for raw in f ):
a.append(columns[c])
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