Re: help on python regular expression named group

Le mercredi 17 juillet 2013 09:46:46 UTC+2, Joshua Landau a écrit : > On 17 July 2013 07:15, wrote: > > > Not sure, I'm correct. I took you precise string to > > > refresh my memory. > > > > I'm glad to see you doing something else, but I don't think you > > understood his problem. Note tha

Re: help on python regular expression named group

On 17 July 2013 07:15, wrote: > Not sure, I'm correct. I took you precise string to > refresh my memory. I'm glad to see you doing something else, but I don't think you understood his problem. Note that his problem has not solution, which a few seconds of Googling has confirmed to me. -- http:/

Re: help on python regular expression named group

Le mardi 16 juillet 2013 08:55:58 UTC+2, Mohan L a écrit : > Dear All, > > > > Here is my script : > > > > #!/usr/bin/python > > > import re > > > > > # A string. > logs = "date=2012-11-28 time=21:14:59" > > > > # Match with named groups. > m = > re.match("(?P(date=(?P[^\s]+))\s+(ti

Re: help on python regular expression named group

On 16 July 2013 16:38, MRAB wrote: > On 16/07/2013 11:18, Mohan L wrote: >> >> I using another third party python script. It takes the regex from >> configuration file. I can't write any code. I have to do all this in >> single regex. >> > A capture group captures a single substring. > > What you'

Re: help on python regular expression named group

On 16/07/2013 11:18, Mohan L wrote: On Tue, Jul 16, 2013 at 2:12 PM, Joshua Landau mailto:jos...@landau.ws>> wrote: On 16 July 2013 07:55, Mohan L mailto:l.mohan...@gmail.com>> wrote: > > Dear All, > > Here is my script : > > #!/usr/bin/python > import r

Re: help on python regular expression named group

On Tue, Jul 16, 2013 at 2:12 PM, Joshua Landau wrote: > On 16 July 2013 07:55, Mohan L wrote: > > > > Dear All, > > > > Here is my script : > > > > #!/usr/bin/python > > import re > > > > # A string. > > logs = "date=2012-11-28 time=21:14:59" > > > > # Match with named groups. > > m = > > > re.m

Re: help on python regular expression named group

On 16 July 2013 07:55, Mohan L wrote: > > Dear All, > > Here is my script : > > #!/usr/bin/python > import re > > # A string. > logs = "date=2012-11-28 time=21:14:59" > > # Match with named groups. > m = > re.match("(?P(date=(?P[^\s]+))\s+(time=(?P[^\s]+)))", > logs) > > # print > print m.groupdic

help on python regular expression named group

Dear All, Here is my script : #!/usr/bin/python import re # A string. logs = "date=2012-11-28 time=21:14:59" # Match with named groups. m = re.match("(?P(date=(?P[^\s]+))\s+(time=(?P[^\s]+)))", logs) # print print m.groupdict() Output: {'date': '2012-11-28', 'datetime': '*date=2012-

Re: PyWart: Python regular expression syntax is not intuitive.

On 1/25/2012 20:24, Devin Jeanpierre wrote: > If all you're going to change is the parser, maybe it'd be easier to > get things to coexist if parsers were pluggable in the re module. > > It's more generally useful, too. Would let re gain a PyParsing/SNOBOL > like expression "syntax", for example. O

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, 25 Jan 2012 13:17:11 -0700, Ian Kelly wrote: > 2) Permitting flags in the regular expression allows different > combinations of flags to be in effect for different parts of complex > regular expressions. You can't do that just by passing in the flags as > an argument. I don't believe Pyt

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, 25 Jan 2012 15:44:35 -0800, Rick Johnson wrote: > I've posted my thoughts and my initial syntax. You (and everyone else) > are free to critic or offer suggestions of your own. Listen, none of > these issues that plague Python are going to be resolved until people > around here set aside th

Re: PyWart: Python regular expression syntax is not intuitive.

On Jan 25, 8:24 pm, Devin Jeanpierre wrote: > On Wed, Jan 25, 2012 at 7:14 PM, Rick Johnson > > wrote: > > It is germane in the fact that i believe PyParsing, re, and my new > > regex module can co-exist in harmony. > > If all you're going to change is the parser, maybe it'd be easier to > get th

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, Jan 25, 2012 at 7:14 PM, Rick Johnson wrote: > It is germane in the fact that i believe PyParsing, re, and my new > regex module can co-exist in harmony. If all you're going to change is the parser, maybe it'd be easier to get things to coexist if parsers were pluggable in the re module.

Re: PyWart: Python regular expression syntax is not intuitive.

On 01/25/2012 06:54 PM, Steven D'Aprano wrote: > The only intuitive interface is the nipple. Everything else is learned. I think young mothers would even disagree with that. It's learned just like everything else in life. Albeit very rapidly. -- http://mail.python.org/mailman/listinfo/python-li

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, 25 Jan 2012 16:14:09 -0800, Rick Johnson wrote: > It is germane in the fact that i believe PyParsing, re, and my new regex > module can co-exist in harmony. You don't have a new regex module. When you have written it, then you will have a new regex module. Until then, you're all talk.

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, 25 Jan 2012 09:16:01 -0800, Rick Johnson wrote: > In particular i find the "extension notation" syntax to be woefully > inadequate. You should be able to infer the action of the extension > syntax intuitively, simply from looking at its signature. I find myself > continually needing to con

Re: PyWart: Python regular expression syntax is not intuitive.

On Jan 25, 5:36 pm, Ian Kelly wrote: > On Wed, Jan 25, 2012 at 2:19 PM, Rick Johnson > > wrote: > > I disagree here. > > Whist some people may be "die-hard" fans of the un-intuitive perl > > regex syntax, i believe many, if not exponentially MORE people would > > like to have a better alternative

Re: PyWart: Python regular expression syntax is not intuitive.

On Jan 25, 5:28 pm, Devin Jeanpierre wrote: > Perhaps you should perform some experiments to prove intuitiveness [of your > syntax]? I've posted my thoughts and my initial syntax. You (and everyone else) are free to critic or offer suggestions of your own. Listen, none of these issues that plagu

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, Jan 25, 2012 at 2:19 PM, Rick Johnson wrote: > I disagree here. > Whist some people may be "die-hard" fans of the un-intuitive perl > regex syntax, i believe many, if not exponentially MORE people would > like to have a better alternative. Do i want to remove the current > "well establishe

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, Jan 25, 2012 at 12:16 PM, Rick Johnson wrote: > In particular i find the "extension notation" syntax to be woefully > inadequate. You should be able to infer the action of the extension > syntax intuitively, simply from looking at its signature. This is nice in theory. I see no reason to

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, Jan 25, 2012 at 2:32 PM, Duncan Booth wrote: > The problem with your idea is that it breaks compatability with other non- > Python regular expression engines. Python didn't invent the (?...) syntax, > it originated with Perl. > > Try complaining to a Perl group inst

Re: PyWart: Python regular expression syntax is not intuitive.

module provides regular expression matching operations *similar > >> to those found in Perl*" (my emphasis). ÿThe goal here is > >> compatibility with existing RE syntaxes, not readability. ÿPerl uses > >> the (?...) syntax, so the re module does too. > > > @Dunca

Re: PyWart: Python regular expression syntax is not intuitive.

t;> to those found in Perl*" (my emphasis). ÿThe goal here is >> compatibility with existing RE syntaxes, not readability. ÿPerl uses >> the (?...) syntax, so the re module does too. > > @Duncan and Ian: > Did you not read the title of my post? :o) " Python regular e

Re: PyWart: Python regular expression syntax is not intuitive.

is).  The goal here is > compatibility with existing RE syntaxes, not readability.  Perl uses > the (?...) syntax, so the re module does too. @Duncan and Ian: Did you not read the title of my post? :o) " Python regular expression syntax is not intuitive." While i understand WHERE the syntax

Re: PyWart: Python regular expression syntax is not intuitive.

On 1/25/2012 12:16 PM, Rick Johnson wrote: (?...) # Base Extension Syntax All extensions are wrapped in parenthesis and start with a question mark, but i believe the question mark was a very bad choice, since the I think that syntax came either from Perl or the pcre library used by several o

Re: PyWart: Python regular expression syntax is not intuitive.

On Wed, Jan 25, 2012 at 10:16 AM, Rick Johnson wrote: > (?...)  # Base Extension Syntax > All extensions are wrapped in parenthesis and start with a question > mark, but i believe the question mark was a very bad choice, since the > question mark is already specific to "zero or one repetitions of

Re: PyWart: Python regular expression syntax is not intuitive.

another char, and the char should NOT be known to RE in any > other place. Maybe the tilde would work? Wait, i have a MUCH better > idea!!! The problem with your idea is that it breaks compatability with other non- Python regular expression engines. Python didn't invent the (?...) sy

Re: PyWart: Python regular expression syntax is not intuitive.

On Jan 25, 11:16 am, Rick Johnson wrote: > {!()...} or (!...) # Non Capturing. Yuck: on second thought, i don't like {!()...}, mainly because non- capturing groups should use the parenthesis delimiters to keep the API consistent. Try this instead --> (!:...) > {NG=identifier...}  # Named Group

PyWart: Python regular expression syntax is not intuitive.

In particular i find the "extension notation" syntax to be woefully inadequate. You should be able to infer the action of the extension syntax intuitively, simply from looking at its signature. I find myself continually needing to consult the docs because of the lacking or misleading style of the c

Re: Need help in Python regular expression

On Fri, 12 Jun 2009 06:20:24 +0100, meryl wrote: On Jun 11, 9:41 pm, "Mark Tolonen" wrote: "meryl" wrote in message > Hi, > I have this regular expression > blockRE = re.compile(".*RenderBlock {\w+}") > it works if my source is "RenderBlock {CENTER}". [snip] ---cod

Re: Need help in Python regular expression

To the OP, I suggest if you haven't yet Kodos, to get it here http://kodos.sourceforge.net/. It's a python regexp debugger, a lifetime saver. Jean-Michel John S wrote: On Jun 11, 10:30 pm, meryl wrote: Hi, I have this regular expression blockRE = re.compile(".*RenderBlock {\w+}") it w

Re: Need help in Python regular expression

2009/6/12 meryl : > On Jun 11, 9:41 pm, "Mark Tolonen" wrote: >> "meryl" wrote in message >> >> > I have this regular expression >... > I try adding ".*" at the end , but it ends up just matching the second > one. If there can be more matches in a line, maybe the non-greedy quantifier ".*?", a

Re: Need help in Python regular expression

On Jun 11, 9:41 pm, "Mark Tolonen" wrote: > "meryl" wrote in message > > news:2d4d8624-043b-4f5f-ae2d-bf73bca3d...@p6g2000pre.googlegroups.com... > > > > > > > Hi, > > > I have this regular expression > > blockRE = re.compile(".*RenderBlock {\w+}") > > > it works if my source is "RenderBlock {CEN

Re: Need help in Python regular expression

On Jun 11, 10:30 pm, meryl wrote: > Hi, > > I have this regular expression > blockRE = re.compile(".*RenderBlock {\w+}") > > it works if my source is "RenderBlock {CENTER}". > > But I want it to work with > 1. RenderTable {TABLE} > > So i change the regexp to re.compile(".*Render[Block|Table] {\w+

Re: Need help in Python regular expression

"meryl" wrote in message news:2d4d8624-043b-4f5f-ae2d-bf73bca3d...@p6g2000pre.googlegroups.com... Hi, I have this regular expression blockRE = re.compile(".*RenderBlock {\w+}") it works if my source is "RenderBlock {CENTER}". But I want it to work with 1. RenderTable {TABLE} So i change the

Need help in Python regular expression

Hi, I have this regular expression blockRE = re.compile(".*RenderBlock {\w+}") it works if my source is "RenderBlock {CENTER}". But I want it to work with 1. RenderTable {TABLE} So i change the regexp to re.compile(".*Render[Block|Table] {\w+}"), but that breaks everything 2. RenderBlock (CENT

Re: python -regular expression - list element

On Jun 25, 2:55 am, antar2 <[EMAIL PROTECTED]> wrote: > Hello, > > I am a beginner in Python and am not able to use a list element for > regular expression, substitutions. > > list1 = [ 'a', 'o' ] > list2 = ['star',  'day', 'work', 'hello'] > > Suppose that I want to substitute the vowels from list

Re: python -regular expression - list element

On Jun 25, 12:32 pm, Ben Finney <[EMAIL PROTECTED]> wrote: > antar2 <[EMAIL PROTECTED]> writes: > > for x in list1: > >    re.compile(x) > >    for y in list2: > >            re.compile(y) > >            if x in y: > >                    z = re.sub(x, 'u', y) > > but this does not work > > You need

Re: python -regular expression - list element

On 2008-06-25, antar2 <[EMAIL PROTECTED]> wrote: > I am a beginner in Python and am not able to use a list element for > regular expression, substitutions. > > list1 = [ 'a', 'o' ] > list2 = ['star', 'day', 'work', 'hello'] > > Suppose that I want to substitute the vowels from list2 that are in >

Re: python -regular expression - list element

antar2 <[EMAIL PROTECTED]> writes: > for x in list1: >re.compile(x) > for y in list2: >re.compile(y) > if x in y: > z = re.sub(x, 'u', y) > but this does not work You need to frotz the hymangirator with spangule. That, or show us the actu

Re: python -regular expression - list element

On Jun 25, 11:55 am, antar2 <[EMAIL PROTECTED]> wrote: > Hello, > > I am a beginner in Python and am not able to use a list element for > regular expression, substitutions. > > list1 = [ 'a', 'o' ] > list2 = ['star', 'day', 'work', 'hello'] > > Suppose that I want to substitute the vowels from lis

python -regular expression - list element

Hello, I am a beginner in Python and am not able to use a list element for regular expression, substitutions. list1 = [ 'a', 'o' ] list2 = ['star', 'day', 'work', 'hello'] Suppose that I want to substitute the vowels from list2 that are in list1, into for example 'u'. In my substitution, I shou

Re: python regular expression help

python regular expression help En Wed, 11 Apr 2007 23:14:01 -0300, Qilong Ren <[EMAIL PROTECTED]> escribió: > Thanks for reply. That actually is not what I want. Strings I am dealing > with may look like this: > s = 'a = 4.5 b = 'h' 'd' c = 4.5 3.5'

Re: python regular expression help

On Apr 11, 11:15 pm, [EMAIL PROTECTED] wrote: > On Apr 11, 9:50 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> > lhs = re.compile(r'\s*(\b\w+\s*=)') > for s in [ "a = 4 b =3.4 5.4 c = 4.5", > "a = 4.5 b = 'h' 'd' c = 4.5 3.5"]: > tokens = lhs.split(s) > results = [tokens[_] + tokens[_+1] for

Re: python regular expression help

On Apr 11, 11:50 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote: > En Wed, 11 Apr 2007 23:14:01 -0300, Qilong Ren <[EMAIL PROTECTED]> > escribió: > > > Thanks for reply. That actually is not what I want. Strings I am dealing > > with may look like this: > > s = 'a = 4.5 b = 'h' 'd' c =

Re: python regular expression help

On Apr 11, 9:50 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote: > En Wed, 11 Apr 2007 23:14:01 -0300, Qilong Ren <[EMAIL PROTECTED]> > escribió: > > > Thanks for reply. That actually is not what I want. Strings I am dealing > > with may look like this: > > s = 'a = 4.5 b = 'h' 'd' c = 4.5

Re: python regular expression help

On Apr 11, 10:50 pm, "Gabriel Genellina" <[EMAIL PROTECTED]> wrote: > En Wed, 11 Apr 2007 23:14:01 -0300, Qilong Ren <[EMAIL PROTECTED]> > escribió: > > > Thanks for reply. That actually is not what I want. Strings I am dealing > > with may look like this: > > s = 'a = 4.5 b = 'h' 'd' c =

Re: python regular expression help

mes = re.compile(r'(\w+)\s*=').findall(s) the corresponding values values = re.split(r'\w+\s*=',s)[1:] It dose not look good but it works. What do you think? Thanks,Qilong - Original Message From: 7stud <[EMAIL PROTECTED]> To: [EMAIL PROTECTED] Sent: Wedn

Re: python regular expression help

En Wed, 11 Apr 2007 23:14:01 -0300, Qilong Ren <[EMAIL PROTECTED]> escribió: > Thanks for reply. That actually is not what I want. Strings I am dealing > with may look like this: > s = 'a = 4.5 b = 'h' 'd' c = 4.5 3.5' > What I want is > a = 4.5 > b = 'h' 'd' > c = 4.5 3.5

Re: python regular expression help

On Apr 11, 7:41 pm, liupeng <[EMAIL PROTECTED]> wrote: > pattern = re.compile(r'\w+\s*=\s*[0-9]*.[0-9]*\s*') > lists = pattern.findall(s) > print lists > ['a=4 ', 'b=3.4 ', 'c=4.5'] > > On Wed, Apr 11, 2007 at 06:10:07PM -0700, Qilong Ren wrote: > > Hi, everyone, > > > I am extracting some informat

Re: python regular expression help

From: liupeng <[EMAIL PROTECTED]> To: python-list@python.org Sent: Wednesday, April 11, 2007 6:41:30 PM Subject: Re: python regular expression help pattern = re.compile(r'\w+\s*=\s*[0-9]*.[0-9]*\s*') lists = pattern.findall(s) print lists ['a=4 ', 'b=3.4 ', 'c=

Re: python regular expression help

pattern = re.compile(r'\w+\s*=\s*[0-9]*.[0-9]*\s*') lists = pattern.findall(s) print lists ['a=4 ', 'b=3.4 ', 'c=4.5'] On Wed, Apr 11, 2007 at 06:10:07PM -0700, Qilong Ren wrote: > Hi, everyone, > > I am extracting some information from a given string using python RE. The > string is ,for example,

python regular expression help

Hi, everyone, I am extracting some information from a given string using python RE. The string is ,for example, s = 'a = 4 b =3.4 5.4 c = 4.5' What I want is : a = 4 b = 3.4 5.4 c = 4.5 Right now I use : pattern = re.compile(r'\w+\s*=\s*.*?\s+') lists = pattern.findall(s) It

Re: Python regular expression

Wehrdamned wrote: > As I understand it, python uses a pcre engine to work with regular > expression. [...] > My question is, then, why expressions like : re.compile('asd|(?-i:QWE)', re.I) [...] > don't work? They are ok in perl... >From http://docs.python.org/lib/module-re.html: This mo

Python regular expression

Hi, As I understand it, python uses a pcre engine to work with regular expression. My question is, then, why expressions like : >>> re.compile('asd|(?-i:QWE)', re.I) Traceback (most recent call last): File "", line 1, in ? File "/usr/lib/python2.4/sre.py", line 180, in compile return _com

Re: Python regular expression question!

Sweet! Thanks so much! -- http://mail.python.org/mailman/listinfo/python-list

Re: Python regular expression question!

unexpected wrote: > > \b matches the beginning/end of a word (characters a-zA-Z_0-9). > > So that regex will match e.g. MULTX-FOO but not MULTX-. > > > > So is there a way to get \b to include - ? No, but you can get the behaviour you want using negative lookaheads. The following regex is effecti

Re: Python regular expression question!

> \b matches the beginning/end of a word (characters a-zA-Z_0-9). > So that regex will match e.g. MULTX-FOO but not MULTX-. > So is there a way to get \b to include - ? -- http://mail.python.org/mailman/listinfo/python-list

Re: Python regular expression question!

"unexpected" <[EMAIL PROTECTED]> writes: > I'm trying to do a whole word pattern match for the term 'MULTX-' > > Currently, my regular expression syntax is: > > re.search(('^')+(keyword+'\\b') \b matches the beginning/end of a word (characters a-zA-Z_0-9). So that regex will match e.g. MULTX-FOO

Python regular expression question!

I'm trying to do a whole word pattern match for the term 'MULTX-' Currently, my regular expression syntax is: re.search(('^')+(keyword+'\\b') where keyword comes from a list of terms. ('MULTX-' is in this list, and hence a keyword). My regular expression works for a variety of different keyword

Re: How to use python regular expression to substitute string value

[EMAIL PROTECTED] writes: > When I try your idea, I have this error > > x, y, width, height = re.findall(pattern, str)[0] > IndexError: list index out of range > > How can I use findall to handle error case? i.e. what if there is no > match? how can I handle it gracefully? This is explained i

Re: How to use python regular expression to substitute string value

When I try your idea, I have this error x, y, width, height = re.findall(pattern, str)[0] IndexError: list index out of range How can I use findall to handle error case? i.e. what if there is no match? how can I handle it gracefully? -- http://mail.python.org/mailman/listinfo/python-list

Re: How to use python regular expression to substitute string value

Are you sure node.data contains newlines? You could try just: print node.data print node.data.split('\n') This should give you an idea. From the interpreter: >>> s = """ ... abc ... def ... xyz""" >>> s.split('\n') ['', 'abc', 'def', 'xyz'] -- http://mail.python.org/mailman/listinfo/python-list

Re: How to use python regular expression to substitute string value

okay, but I have a simpler question, how can I split using only "\n"? I try this: strings = node.data.split("\n"); print node.data for str in strings: print str where node.data has multiple lines, but in the for loop, I don't see str gets pr

Re: How to use python regular expression to substitute string value

You don't really need regexes for this. Assuming there is no whitespace in any of your values, it should be really easy to parse the string. s = 'x:11 y:0 w:760 h:19 area:14440 areaPerCent:0 totalAreaPerCent:-3.08011e+16 type:3 path:///-/1/1' s.split() # break the string on whitespace > ['x:11',

Re: How to use python regular expression to substitute string value

Thanks. But i don't understand why I need to do this: x. . area = map (lambda x: int(x), re.findall (pattern, line)[0] if i have the value already by doing this: x, y, width, height, area = re.findall(pattern, line)[0] print "rect x=\"%(x)s\" y=\"%(y)s\" width=\"%(width)s\" height=\"%(height)s\"

Re: How to use python regular expression to substitute string value

[EMAIL PROTECTED] writes: > Hi, > I am new to python. I would like to know how to use python regular > expression to substitute string value? > I have an input string like this: > x:11 y:0 w:760 h:19 area:14440 areaPerCent:0 > totalAreaPerCent:-3.08011e+16 type:3 path:///-/1

How to use python regular expression to substitute string value

Hi, I am new to python. I would like to know how to use python regular expression to substitute string value? I have an input string like this: x:11 y:0 w:760 h:19 area:14440 areaPerCent:0 totalAreaPerCent:-3.08011e+16 type:3 path:///-/1/1 and I would like to convert it to: rect x="11&

Re: where to find the doc about python regular expression?

ÒÊÃÉɽÈË wrote: > thanks Did you try Google: First hit is: -- Klaus Alexander Seistrup Magnetic Ink, Copenhagen, Denmark http://magnetic-ink.dk/ -- http://mail.python.org/mailman

where to find the doc about python regular expression?

thanks -- http://mail.python.org/mailman/listinfo/python-list