Re: Python and Combinatorics

On Oct 25, 12:20 am, none <""atavory\"@(none)"> wrote: > Hello, > > Is there some package to calculate combinatorical stuff like (n over > k), i.e., n!/(k!(n - k!) ? > > I know it can be written in about 3 lines of code, but still... > > Thanks, > > Ami http

Re: Python and Combinatorics

none wrote: > Is there some package to calculate combinatorical stuff like (n over > k), i.e., n!/(k!(n - k!) ? Yes, in SciPy. Alan Isaac >>> from scipy.misc.common import comb >>> help(comb) Help on function comb in module scipy.misc.common: comb(N, k, exact=0) Combinations of N thin

Re: Python and Combinatorics

[EMAIL PROTECTED] wrote: > On Oct 24, 5:20 pm, none <""atavory\"@(none)"> wrote: >> Hello, >> >> Is there some package to calculate combinatorical stuff like (n over >> k), i.e., n!/(k!(n - k!) ? > > Sure, the gmpy module. > Excellent, many thanks! -- http://mail.python.org/mail

Re: Python and Combinatorics

On Oct 24, 5:20 pm, none <""atavory\"@(none)"> wrote: > Hello, > > Is there some package to calculate combinatorical stuff like (n over > k), i.e., n!/(k!(n - k!) ? Sure, the gmpy module. >>> import gmpy >>> for m in xrange(10): for n in xrange(m+1): print

Python and Combinatorics

Hello, Is there some package to calculate combinatorical stuff like (n over k), i.e., n!/(k!(n - k!) ? I know it can be written in about 3 lines of code, but still... Thanks, Ami -- http://mail.python.org/mailman/listinfo/python-list

Re: Python and Combinatorics

Nic wrote: > In my example I've chosen the number 3. > How should I change the Python code in order to select another number > (e.g. 7)? Here is a parameterized render(). def render(w, h, suffixes="ab"): pairs = list(unique(range(1, h+1), 2)) for item in unique(pairs, w): for suf

Re: Python and Combinatorics

Thanks a bunch. Both the codes are fine. Only one question, if you allow. In my example I've chosen the number 3. How should I change the Python code in order to select another number (e.g. 7)? Thanks. Nic -- http://mail.python.org/mailman/listinfo/python-list

Re: Python and Combinatorics

Nic wrote: > Hello, > I've a problem in defining a good Python code useful to articulate the > following algorithm. > Can you help me please? > Thanks a bunch, > Nic > > 1. Insert a number "n". > Example: 3 > > 2. List all the numbers < or = to n. > Example: 1,2,3. > > 3. Combine the listed number

Re: Python and Combinatorics

Nic wrote: >> PS: Please don't top-post. You probably overlooked that :-) Here's a naive implementation: from itertools import izip def unique(items, N): assert N > 0 if N == 1: for item in items: yield item, else: for index, item in enumerate(items):

Re: Python and Combinatorics

I forgot them. Sorry. They should be included. Nic "Peter Otten" <[EMAIL PROTECTED]> ha scritto nel messaggio news:[EMAIL PROTECTED] > Nic wrote: > > [Algorithm that I may have misunderstood] > >> 12a 13a 23a >> 12a 13b 23a >> 12a 13b 23b >> 12b 13a 23a >> 12b 13b 23a >> 12b 13b 23b > > What abou

Re: Python and Combinatorics

Nic wrote: [Algorithm that I may have misunderstood] > 12a 13a 23a > 12a 13b 23a > 12a 13b 23b > 12b 13a 23a > 12b 13b 23a > 12b 13b 23b What about 12a 13a 23b and 12b 13a 23b? Peter PS: Please don't top-post. -- http://mail.python.org/mailman/listinfo/python-list

Python and Combinatorics

Hello, I've a problem in defining a good Python code useful to articulate the following algorithm. Can you help me please? Thanks a bunch, Nic 1. Insert a number "n". Example: 3 2. List all the numbers < or = to n. Example: 1,2,3. 3. Combine the listed numbers each other. Example: 12 13 23 4.