[EMAIL PROTECTED] wrote:
> Bruno Desthuilliers wrote:
> > def printVerbose(*args, **kwargs):
> >
> > > if VERBOSE in globals:
> > > for a in args:
> > > if a in globals:
> > > value = globals[a]
> >
for k, v in kwargs.iteritems():
> > >
Simon Dahlbacka wrote:
> as you have been told, there is no way to get a variable's name
Well, if you really want to, you can get all the names bound to a given
object:
def get_names(obj):
g = globals()
names = []
for name in g:
if g[name] is obj:
names.appe
Simon Dahlbacka wrote:
> as you have been told, there is no way to get a variable's name, take a
> look at http://effbot.org/zone/python-objects.htm to find out why this
> is so.
Thanks, Simon, for the link.
--
Regards,
Travis Spencer
--
http://mail.python.org/mailman/listinfo/python-list
Bruno Desthuilliers wrote:
> [EMAIL PROTECTED] a écrit :
> > globals = {}
>
> globals() is a builtin function, you should no shadow it.
Oh, woops. I'll fix that.
> def printVerbose(*args, **kwargs):
>
> > if VERBOSE in globals:
> > for a in args:
> > if a in globals:
> >
[EMAIL PROTECTED] a écrit :
> Hey,
>
> I am trying to write a function that takes an arbitrary number of
> arguments and does one of two things. If the variable is a key in a
> dictionary, it prints the key and its value. Otherwise, if any of the
> variables isn't in the dictionary, the function
as you have been told, there is no way to get a variable's name, take a
look at http://effbot.org/zone/python-objects.htm to find out why this
is so.
--
http://mail.python.org/mailman/listinfo/python-list
Hey,
I am trying to write a function that takes an arbitrary number of
arguments and does one of two things. If the variable is a key in a
dictionary, it prints the key and its value. Otherwise, if any of the
variables isn't in the dictionary, the function prints the variable's
name and value.
