Fredrik Lundh wrote:
[snip..]
>
> the algorithm is:
>
> x, y = im.size
> if x > size[0]: y = max(y * size[0] / x, 1); x = size[0]
> if y > size[1]: x = max(x * size[1] / y, 1); y = size[1]
> size = x, y
>
> that is, it shrinks the image horizontally first, and it then shrinks the
>
Roger wrote:
> I need to calculate the thumbnail sizes PILL will produce from an image.
> In most cases I can divide and round by adding .5, but PIL seems to
> round differently on odd sized images.
>
> For example, I want to reduce an 800x816 image to have a maximum size of
> 697. (697/816) * 80
I need to calculate the thumbnail sizes PILL will produce from an image.
In most cases I can divide and round by adding .5, but PIL seems to
round differently on odd sized images.
For example, I want to reduce an 800x816 image to have a maximum size of
697. (697/816) * 800 = 683.33, so my ro
