On Sep 11, 8:04 pm, Arnaud Delobelle <[EMAIL PROTECTED]> wrote:
> On Sep 11, 5:40 pm, "Giampaolo Rodola'" <[EMAIL PROTECTED]> wrote:
>
>
>
> > Hi,
> > I'm trying to implement a function which returns whether a path is a
> > subpath of another one (e.g. /a/b/c is a subpath of /a/b).
> > I wrote this
Diez B. Roggisch wrote:
Any reason why
os.path.normpath(a).startswith(os.normpath(b)) doesn't do the trick?
Except for the trivial type, you mean? That depends on whether "c:\foo"
should be seen as a subpath to "c:\foobar" or not. I'd probably go for
(also untested):
def issubpath(a, b)
Giampaolo Rodola' schrieb:
Hi,
I'm trying to implement a function which returns whether a path is a
subpath of another one (e.g. /a/b/c is a subpath of /a/b).
I wrote this function which apparently seems to work fine:
import os
def issubpath(path1, path2):
"""Return True if path1 is a sub p
On Sep 11, 5:40 pm, "Giampaolo Rodola'" <[EMAIL PROTECTED]> wrote:
> Hi,
> I'm trying to implement a function which returns whether a path is a
> subpath of another one (e.g. /a/b/c is a subpath of /a/b).
> I wrote this function which apparently seems to work fine:
>
> import os
>
> def issubpath(p
Hi,
I'm trying to implement a function which returns whether a path is a
subpath of another one (e.g. /a/b/c is a subpath of /a/b).
I wrote this function which apparently seems to work fine:
import os
def issubpath(path1, path2):
"""Return True if path1 is a sub path of path2."""
if path1
