On 6/2/2013 3:09 PM, Mok-Kong Shen wrote:
Am 28.05.2013 17:35, schrieb Grant Edwards:
On 2013-05-26, Mok-Kong Shen wrote:
I don't understand why with the code:
for k in range(8,12,1):
print(k.to_bytes(2,byteorder='big'))
one gets the following output:
b'\x00\x08'
b'\x0
Am 28.05.2013 17:35, schrieb Grant Edwards:
On 2013-05-26, Mok-Kong Shen wrote:
I don't understand why with the code:
for k in range(8,12,1):
print(k.to_bytes(2,byteorder='big'))
one gets the following output:
b'\x00\x08'
b'\x00\t'
b'\x00\n'
b'\x00\x0b'
I mea
On 2013-05-26, Mok-Kong Shen wrote:
> I don't understand why with the code:
>
> for k in range(8,12,1):
> print(k.to_bytes(2,byteorder='big'))
>
> one gets the following output:
>
> b'\x00\x08'
> b'\x00\t'
> b'\x00\n'
> b'\x00\x0b'
>
> I mean the 2nd and 3rd should be b'\
On 5/26/2013 8:02 AM, Mok-Kong Shen wrote:
for k in range(8,12,1):
print(k.to_bytes(2,byteorder='big'))
http://bugs.python.org/issue9951
http://bugs.python.org/issue3532
import binascii as ba
for k in range(8,12,1):
print(ba.hexlify(k.to_bytes(2,byteorder='big')))
>>>
b'0008'
b'0
On Sun, May 26, 2013 at 10:02 PM, Mok-Kong Shen
wrote:
> I don't understand why with the code:
>
>for k in range(8,12,1):
> print(k.to_bytes(2,byteorder='big'))
>
> one gets the following output:
>
>b'\x00\x08'
>b'\x00\t'
>b'\x00\n'
>b'\x00\x0b'
>
> I mean the 2nd and 3rd
I don't understand why with the code:
for k in range(8,12,1):
print(k.to_bytes(2,byteorder='big'))
one gets the following output:
b'\x00\x08'
b'\x00\t'
b'\x00\n'
b'\x00\x0b'
I mean the 2nd and 3rd should be b'\x00\x09' and b'x00\x0a'.
Anyway, how could I get the output in t
