To possibly clearify what the others have said, group() is the same as
saying group(0). Group is, if I recall correctly, supposed to return
the n-th subpattern from the regular expression (subpatterns, as you
know, being indicated by parenthises).
Hope that helps :)
-Wes
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Why doesn't group have an argument? group() or group(0) returns what
the pattern matched, not what it returns.
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Hi David,
b.group() is equivalent to b.group(0), the entire RE
match. (^(.*?)\.) will give you 'dfsf.' for that input string.
What you want is b.group(1), the subgroup you're looking for inside
the main RE. (.*?) which gives you 'dfsf', which is what you're
looking for.
Cheers,
Hello
It seems the grouping feature isn't behaving correctly.
In [1]: a = 'dfsf.oct.ocfe'
In [2]: b = re.match(r'^(.*?)\.', a); b.group()
'dfsf.'
The expected result is 'dfsf'. Why did the regexp grab that period at
the end?
David
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