Re: Newbie question: Allocation vs references

2005-06-02 Thread Steven Bethard
Stian Søiland wrote: > There are several ways to create a copy of a list: [snip] > a2 = list(a) # create a new list object out of any sequence I'll just point out that FWIW, this is by far my favorite idiom of the ones offered because it applies to pretty much all the builtin container typ

Re: Newbie question: Allocation vs references

2005-06-02 Thread Stian =?iso-8859-1?Q?S=F8iland?=
On 2005-06-02 14:43:40, Jan Danielsson wrote: > a = [ 'Foo', 'Bar' ] > b = [ 'Boo', 'Far' ] > q = [ a, b ] >Or, better yet, how do I store a and b in q, and then tell Python > that I want a and b to point to new lists, without touching the contents > in q? There are several ways to create a

Re: Newbie question: Allocation vs references

2005-06-02 Thread rzed
Jan Danielsson <[EMAIL PROTECTED]> wrote in news:[EMAIL PROTECTED]: > Hello all, > > Behold: > > -- > a = [ 'Foo', 'Bar' ] > b = [ 'Boo', 'Far' ] > q = [ a, b ] > > print q[0][0] > print q[1][1] > > a[0] = 'Snoo' > b[1] = 'Gnuu' > > print q[0][0] > print q[1][1] > -- > > Thi

Newbie question: Allocation vs references

2005-06-02 Thread Jan Danielsson
Hello all, Behold: -- a = [ 'Foo', 'Bar' ] b = [ 'Boo', 'Far' ] q = [ a, b ] print q[0][0] print q[1][1] a[0] = 'Snoo' b[1] = 'Gnuu' print q[0][0] print q[1][1] -- This will output: Foo Far Snoo Gnuu I assume it does so because q stores _references_ to a and b. How would d