On 2/16/2016 7:46 AM, srinivas devaki wrote:
Hi,
a = b = c
as an assignment doesn't return anything, i ruled out a = b = c as
chained assignment, like a = (b = c)
SO i thought, a = b = c is resolved as
a, b = [c, c]
https://docs.python.org/3/reference/simple_stmts.html#assignment-statements
"
On Tue, Feb 16, 2016 at 6:35 PM, Sven R. Kunze wrote:
>
> First, the rhs is evaluated.
> Second, the lhs is evaluated from left to right.
Great, I will remember these two lines :)
On Tue, Feb 16, 2016 at 8:46 PM, Steven D'Aprano wrote:
> _temp = c
> a = _temp
> b = _temp
> del _temp
>
>
> except
On Tue, 16 Feb 2016 11:46 pm, srinivas devaki wrote:
> Hi,
>
> a = b = c
>
> as an assignment doesn't return anything, i ruled out a = b = c as
> chained assignment, like a = (b = c)
> SO i thought, a = b = c is resolved as
> a, b = [c, c]
That is one way of thinking of it. A better way would b
On 16.02.2016 14:05, Sven R. Kunze wrote:
Hi Srinivas,
I think the tuple assignment you showed basically nails it.
First, the rhs is evaluated.
Second, the lhs is evaluated from left to right.
Completely wrong?
Best,
Sven
As you mentioned swapping. The following two statements do the same (
Hi Srinivas,
On 16.02.2016 13:46, srinivas devaki wrote:
Hi,
a = b = c
as an assignment doesn't return anything, i ruled out a = b = c as
chained assignment, like a = (b = c)
SO i thought, a = b = c is resolved as
a, b = [c, c]
at-least i fixed in my mind that every assignment like operation
Hi,
a = b = c
as an assignment doesn't return anything, i ruled out a = b = c as
chained assignment, like a = (b = c)
SO i thought, a = b = c is resolved as
a, b = [c, c]
at-least i fixed in my mind that every assignment like operation in
python is done with references and then the references a
