You can try this :
>>> l = [(2001, 5, 2),(2111,3,3),(1984, 3, 1), (2001, 1, 1)]
>>> l.sort(lambda x = l[0],y = l[1] : cmp((x[1],x[2]),(y[1],y[2])))
- Original Message -
From: "Volker Grabsch" <[EMAIL PROTECTED]>
To:
Sent: Saturday, May 14, 2005 7:09 A
Volker Grabsch wrote:
> Peter Hansen wrote:
>
>>Or just use the .timetuple() method on datetime objects and sort on the
>>8th element of the 9-element tuple, which is the day-of-the-year.
>
> An interesting idea. But wouldn't sorting by (dd.month,dd.day) be more
> effective?
Depending on the me
vincent wehren wrote:
>
>| > If you don't care about the year, why not just "normalize" the year
>| > to all be the same using the replace method of the date instance?
>|
>| That's a very bad idea. In my example, this would work, but in "reality"
>| I don't sort datetime objects, of course! (Is th
"Volker Grabsch" <[EMAIL PROTECTED]> schrieb im
Newsbeitrag news:[EMAIL PROTECTED]
| vincent wehren wrote:
| >
| > If you don't care about the year, why not just "normalize" the year
| > to all be the same using the replace method of the date instance?
|
| That's a very bad idea. In my example, t
Peter Hansen wrote:
>
> Or just use the .timetuple() method on datetime objects and sort on the
> 8th element of the 9-element tuple, which is the day-of-the-year.
An interesting idea. But wouldn't sorting by (dd.month,dd.day) be more
effective?
In other words: Does .timetuple() create a tuple,
vincent wehren wrote:
>
> If you don't care about the year, why not just "normalize" the year
> to all be the same using the replace method of the date instance?
That's a very bad idea. In my example, this would work, but in "reality"
I don't sort datetime objects, of course! (Is there any real a
Steven Bethard wrote:
> Robert Kern wrote:
> def mykey(d):
> return (d.month, d.day)
>
> The point here is that rather than chaining cmp() calls with ors, you
> should just use a tuple -- the standard comparison order in tuples is
> exactly what you're looking for.
That's an excel
Robert Kern wrote:
> I find that using the "key" argument to sort is much nicer than "cmp"
> for these tasks.
>
> In [5]:L = [datetime.date(2005,5,2), datetime.date(1984,12,15),
> datetime.date(1954,1,1)]
>
> In [7]:L.sort(key=lambda x: (x.month, x.day))
>
> In [8]:L
> Out[8]:
> [datetime.date
vincent wehren wrote:
> "Volker Grabsch" <[EMAIL PROTECTED]> schrieb im
> Newsbeitrag news:[EMAIL PROTECTED]
> | However, I don't want to sort them the default way. These are birthdays,
> | so only the month and day do matter, not the year. E.g.:
> |
...
> If you don't care about the year, why not
Volker Grabsch wrote:
> Hello!
>
> Ich just found a very nice 'pythonic' solution for an often appearing
> problem. I didn't find it documented anywhere, so I'm posting it here.
> If this isn't new in any way, I'd really like to get to know it.
>
> Example problem:
> I have some "datetime" object
"Volker Grabsch" <[EMAIL PROTECTED]> schrieb im
Newsbeitrag news:[EMAIL PROTECTED]
| Hello!
|
| Ich just found a very nice 'pythonic' solution for an often appearing
| problem. I didn't find it documented anywhere, so I'm posting it here.
| If this isn't new in any way, I'd really like to get to
Hello!
Ich just found a very nice 'pythonic' solution for an often appearing
problem. I didn't find it documented anywhere, so I'm posting it here.
If this isn't new in any way, I'd really like to get to know it.
Example problem:
I have some "datetime" objects and want to sort them, as here:
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