bdsatish <[EMAIL PROTECTED]> wrote:
> How does (a/b) work when both 'a' and 'b' are pure integers ?
>
>>> (9/2)
> 4
>
>>> (-9/2)
> -5
>
> Why is it -5 ? I expect it to be -4 ? Because, in C/C++, 9/2 is 4 and
> so negative of it, (-9/2) is -4.
Some background on the situation:
Integer division and
On Apr 11, 6:06 am, casevh <[EMAIL PROTECTED]> wrote:
> On Apr 10, 9:28 pm, bdsatish <[EMAIL PROTECTED]> wrote:
>
> > How does (a/b) work when both 'a' and 'b' are pure integers ?
>
> Python defines the quotient and remainder from integer division so
> that a = qb + r and 0<=r < abs(b). C/C++ lets
On Apr 10, 9:28 pm, bdsatish <[EMAIL PROTECTED]> wrote:
> How does (a/b) work when both 'a' and 'b' are pure integers ?
Python defines the quotient and remainder from integer division so
that a = qb + r and 0<=r < abs(b). C/C++ lets the remainder be
negative.
>>> divmod(-9,2)
(-5, 1)
>>> divmod(9
it rounds down. 4 is less than 4.5
and -5 is less than -4.5.
On Thu, 2008-04-10 at 21:28 -0700, bdsatish wrote:
> How does (a/b) work when both 'a' and 'b' are pure integers ?
>
> >> (9/2)
> 4
>
> >> (-9/2)
> -5
>
> Why is it -5 ? I expect it to be -4 ? Because, in C/C++, 9/2 is 4 and
> so n
bdsatish wrote:
> How does (a/b) work when both 'a' and 'b' are pure integers ?
>
>>> (9/2)
> 4
>
>>> (-9/2)
> -5
>
> Why is it -5 ? I expect it to be -4 ? Because, in C/C++, 9/2 is 4 and
> so negative of it, (-9/2) is -4.
>
> What should I do to get C-like behavior ?
Use C?
regards
Steve
-
How does (a/b) work when both 'a' and 'b' are pure integers ?
>> (9/2)
4
>> (-9/2)
-5
Why is it -5 ? I expect it to be -4 ? Because, in C/C++, 9/2 is 4 and
so negative of it, (-9/2) is -4.
What should I do to get C-like behavior ?
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