> J (J) wrote:
>J> And now I'm looking at subprocess and I can set shell=True and it will
>J> intrepret special characters like &
>J> So could I do something like this:
>J> for item in pathlist:
>J> subprocess.Popen('rsync command &', shell=True)
>J> and simply wait unti they are all d
On Mar 10, 4:52 pm, J wrote:
> I'm working on a project and thought I'd ask for a suggestion on how
> to proceed (I've got my own ideas, but I wanted to see if I was on the
> right track)
>
> For now, I've got this:
>
> def main():
> ## get our list of directories to refresh
> releases=sys.arg
On Wed, Mar 10, 2010 at 18:03, MRAB wrote:
> Are you sure that you would gain from doing more than one at a time?
>
> The bottleneck will probably be the speed of your network connection,
> and if that's working at its maximum speed with one sync then doing
> several concurrently won't save any ti
J wrote:
I'm working on a project and thought I'd ask for a suggestion on how
to proceed (I've got my own ideas, but I wanted to see if I was on the
right track)
For now, I've got this:
def main():
## get our list of directories to refresh
releases=sys.argv[1:]
if len(releases) < 1:
On 03/10/10 21:52, J wrote:
I'm working on a project and thought I'd ask for a suggestion on how
to proceed (I've got my own ideas, but I wanted to see if I was on the
right track)
Well I can't speak with authority but I would go into similar lines,
especially since you want to call an externa
On Wed, Mar 10, 2010 at 16:52, J wrote:
> the quick and dirty would be (as I'm imagining it at the moment):
> for path in pathlist:
> chdir into path
> execute rsync or zsync
>
> but that gets me moving into one dir, updating, then moving into another.
>
> What I was wondering about though,
I'm working on a project and thought I'd ask for a suggestion on how
to proceed (I've got my own ideas, but I wanted to see if I was on the
right track)
For now, I've got this:
def main():
## get our list of directories to refresh
releases=sys.argv[1:]
if len(releases) < 1:
print
