On 03/14/2013 04:12 PM, ch.valdera...@gmail.com wrote:
Taking a wild guess, I think that you are using a Samba share on a Linux
server. A file "FILENAME.xml;" was accidentally creating on this share
from the Linux filesystem layer, since Linux will allow you to use
semicolons in file names.
> Taking a wild guess, I think that you are using a Samba share on a Linux
>
> server. A file "FILENAME.xml;" was accidentally creating on this share
>
> from the Linux filesystem layer, since Linux will allow you to use
>
> semicolons in file names. But samba enforces the same restrictions
On Wed, 13 Mar 2013 15:35:19 -0700, ch.valderanis wrote:
> Traceback (most recent call last):
> File "createsubmitfiles.py", line 12, in
> newfile=open(newname,'w')
> IOError: [Errno 27] File too large: 'FILENAME.sub;'
>
> I have chang
dvice:
Here it the error:
Traceback (most recent call last):
File "createsubmitfiles.py", line 12, in
newfile=open(newname,'w')
IOError: [Errno 27] File too large: 'FILENAME.sub;'
I have changed the actual filename reported by the traceback.
FILENAME.xml does exist befor
On Wed, 13 Mar 2013 09:53:17 -0700, ch.valderanis wrote:
> Hi,
>
> Relatively newcomer here.
> The following code fails with the above error: python version used 2.6.2
> under linux
Which part of the code fails? Please copy and paste the entire traceback,
starting with the line "Traceback (most
Hi,
Relatively newcomer here.
The following code fails with the above error:
python version used 2.6.2 under linux
filestring='somestring'
for files in glob.glob('*'):
f2=open(files.replace('.xml','.sub'),'w')
f2.write(filestring+files)
f2.close()
The glob commands retur
