You're actually calling the read2() function from within read2(). This
is called recursion, and it is *not* what you want in this case, since
it unnecessarily fills up your call stack. Remember that a while loop
automatically goes back to the top without you having to re-call your
function. I w
oops, embarrassing, I created the while loop not to use recursion then
I still did...
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ssecorp wrote:
in read2 it never quits when I write quit, why?
def read():
expr = raw_input("Lisp> ")
if expr != "quit":
print parse(expr)
read()
else:
print "Good session!"
def read2():
expr = ""
while expr != "quit":
expr = raw_input("Lisp>
def read2():
expr = ""
while expr != "quit":
expr = raw_input("Lisp> ")
print parse(expr)
read2()
^
print "Good session!"
You shouldn't call read2() inside read2()...
just remove that line and retry...
Each time you call read2() recursivel
in read2 it never quits when I write quit, why?
def read():
expr = raw_input("Lisp> ")
if expr != "quit":
print parse(expr)
read()
else:
print "Good session!"
def read2():
expr = ""
while expr != "quit":
expr = raw_input("Lisp> ")
print
