On Sat, May 14, 2011 at 7:17 PM, Chris Angelico wrote:
> You're right. It needs a while loop instead of the if (and some slight
> reordering):
>
> def ints():
> i=0
> queue=[]
> while True:
> if queue: # see other thread, this IS legal and pythonic and
> quite sensible
> sen
Chris Angelico wrote:
> For what you're doing, there's a little complexity. If I understand,
> you want send() to be like an ungetc call... you could do that like
> this:
>
>
> def ints():
>i=0
>while True:
>sent=(yield i)
>if sent is not None:
> yield None #
On Sun, May 15, 2011 at 11:05 AM, Ian Kelly wrote:
> Actually, this won't work, because the value of the "yield None" gets
> ignored. Thus if you try to call send() twice in a row, the generator
> the treats second send() as if it were a next(), and it is not
> possible to have more than one item
On Sat, May 14, 2011 at 6:47 PM, Chris Angelico wrote:
> def ints():
> i=0
> queue=[]
> while True:
> if queue: # see other thread, this IS legal and pythonic and
> quite sensible
> sent=(yield queue.pop(0))
> else:
> sent=(yield i)
> i+=1
>
On Sat, May 14, 2011 at 6:08 PM, Victor Eijkhout wrote:
> I thought the send call would push the value "2" at the front of the
> queue. Instead it coughs up the 2, which seems senseless to me.
>
> 1/ How should I view the send call? I'm reading the manual and dont' get
> it
There is no queue unle
On Sat, May 14, 2011 at 5:08 PM, Victor Eijkhout wrote:
> #! /usr/bin/env python
>
> def ints():
> i=0
> while True:
> yield i
> i += 1
>
> gen = ints()
> while True:
> i = gen.next()
> print i
> if i==5:
> r = gen.send(2)
> print "return:",r
> if i>10
On Sun, May 15, 2011 at 10:08 AM, Victor Eijkhout wrote:
> yield i
> r = gen.send(2)
When you send() something to a generator, it becomes the return value
of the yield expression. See the example here:
http://docs.python.org/whatsnew/2.5.html#pep-342-new-generator-features
For wha
Victor Eijkhout wrote:
> #! /usr/bin/env python
>
> def ints():
> i=0
> while True:
> yield i
> i += 1
>
> gen = ints()
> while True:
> i = gen.next()
> print i
> if i==5:
> r = gen.send(2)
> print "return:",r
> if i>10:
> break
>
#! /usr/bin/env python
def ints():
i=0
while True:
yield i
i += 1
gen = ints()
while True:
i = gen.next()
print i
if i==5:
r = gen.send(2)
print "return:",r
if i>10:
break
I thought the send call would push the value "2" at the fron
