On Tue, Jul 19, 2011 at 7:20 AM, J wrote:
> Hi guys,
>
> Thank you for your suggestions. I have managed to get my whole script to
> execute in under 10 seconds by changing the 'for loop' I posted above to the
> following:-
>
> for opco in Cn:
> for service in Cn[opco]:
> a
Hi guys,
Thank you for your suggestions. I have managed to get my whole script to
execute in under 10 seconds by changing the 'for loop' I posted above to the
following:-
for opco in Cn:
for service in Cn[opco]:
ack = set(Cn[opco][service]['RECV']) & set(Pr['13'])
On 01/-10/-28163 02:59 PM, J wrote:
Hello,
I am looking to improve the performance of the following piece of Python code:-
for cc in StatusContainer:
for srv in StatusContainer[cc]:
for id in StatusContainer[cc][srv]['RECV']:
if id in StageContain
On 07/19/2011 04:36 AM, J wrote:
Someone in a different forum suggested that I use 'binary
search' to iterate through the dictionaries
I'm not sure what they were smoking...a binary search is useful
for finding a thing in a sorted list. It looks like your data is
not sorted (strike #1) and i
J wrote:
> I am looking to improve the performance of the following piece of Python
> code:-
>
> for cc in StatusContainer:
> for srv in StatusContainer[cc]:
> for id in StatusContainer[cc][srv]['RECV']:
> if id in StageContainer['13']:
> StatusContainer[c
Hello,
I am looking to improve the performance of the following piece of Python code:-
for cc in StatusContainer:
for srv in StatusContainer[cc]:
for id in StatusContainer[cc][srv]['RECV']:
if id in StageContainer['13']:
