Gerard Flanagan wrote:
> [EMAIL PROTECTED] wrote:
> > I have a list
> >
> > x = [0] * 2
> > x = x * [2]
> > x[1,1] = 7
> >
> > This gives me the x value
> > [[0,0] [0,0] [0,0] [0,7]]
> >
> > I want to get the indices of the value 7.
> > i.e. something like
> > i = a.index(max(a)) gives me '1'
> >
[EMAIL PROTECTED] wrote:
> I have a list
>
> x = [0] * 2
> x = x * [2]
> x[1,1] = 7
>
> This gives me the x value
> [[0,0] [0,0] [0,0] [0,7]]
>
> I want to get the indices of the value 7.
> i.e. something like
> i = a.index(max(a)) gives me '1'
>
> This only gives me the index in one dimension. Is
[EMAIL PROTECTED] wrote:
> I have a list
>
> x = [0] * 2
> x = x * [2]
You're certainly not doing that.
>>> x = [0] * 2
>>> x = x * [2]
Traceback (most recent call last):
File "", line 1, in ?
TypeError: can't multiply sequence by non-int
And even if you *do* do what it looks like you think y
I have a list
x = [0] * 2
x = x * [2]
x[1,1] = 7
This gives me the x value
[[0,0] [0,0] [0,0] [0,7]]
I want to get the indices of the value 7.
i.e. something like
i = a.index(max(a)) gives me '1'
This only gives me the index in one dimension. Is there any method by
which I can get (1,1) as the
