> a = now()
> delta = ReltaiveDateTime(days=+6, weekday(mx.DateTime.Friday, 0))
> Next Friday: a+delta
> a: march 23
> a+delta: Gives me March 31st and not March 24th
> Any ideas?
Just an off-beat idea: use Python's datetime instead of mx.DateTime,
and my recur module:
http://projects.amor.org/mis
On 24/03/2006 6:30 AM, vj wrote:
> I figured out how to do it. This does not work:
>
> delta = ReltaiveDateTime(days=0, weekday(mx.DateTime.Friday, 0))
>
> But this works:
>
> delta = ReltaiveDateTime(days=+0, weekday(mx.DateTime.Friday, 0))
>
vj, NEITHER of those work, because you still have
Thanks for pointing out that the days=+0 is not necessary. Your other
points are well noted.
Thanks
VJ
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On 24/03/2006 5:18 AM, Dennis Lee Bieber wrote:
> On 23 Mar 2006 09:37:13 -0800, "vj" <[EMAIL PROTECTED]> declaimed the
> following in comp.lang.python:
>
>
>>I'm doing:
>>
>>a = now()
>>delta = ReltaiveDateTime(days=+6, weekday(mx.DateTime.Friday, 0))
>>Next Friday: a+delta
>>
>>a: march 23
>>a+
I figured out how to do it. This does not work:
delta = ReltaiveDateTime(days=0, weekday(mx.DateTime.Friday, 0))
But this works:
delta = ReltaiveDateTime(days=+0, weekday(mx.DateTime.Friday, 0))
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I'm doing:
a = now()
delta = ReltaiveDateTime(days=+6, weekday(mx.DateTime.Friday, 0))
Next Friday: a+delta
a: march 23
a+delta: Gives me March 31st and not March 24th
Any ideas?
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