In article <[EMAIL PROTECTED]>,
[EMAIL PROTECTED] wrote:
> Let's say I have two dictionaries:
> dict1 is 1:23, 2:76, 4:56
> dict2 is 23:A, 76:B, 56:C
>
> How do I get a dictionary that is
> 1:A, 2:B, 4:C
The following should work:
j = dict((k, dict2[dict1[k]]) for k in dict1 if dict1[k]
[EMAIL PROTECTED] wrote:
> Let's say I have two dictionaries:
> dict1 is 1:23, 2:76, 4:56
> dict2 is 23:A, 76:B, 56:C
>
> How do I get a dictionary that is
> 1:A, 2:B, 4:C
>
Just copy/paste the following source code to a file and run it:
sourceCodeToExecute = """
dict1 = { 1:23,2:76,
Op 2006-02-27, [EMAIL PROTECTED] schreef <[EMAIL PROTECTED]>:
> Let's say I have two dictionaries:
> dict1 is 1:23, 2:76, 4:56
> dict2 is 23:A, 76:B, 56:C
>
> How do I get a dictionary that is
> 1:A, 2:B, 4:C
Well how about the straight forward:
dict3 = {}
for key, value in dict1.iteritems()
> Let's say I have two dictionaries:
> dict1 is 1:23, 2:76, 4:56
> dict2 is 23:A, 76:B, 56:C
>
> How do I get a dictionary that is
> 1:A, 2:B, 4:C
>>> d1={1:23,2:76,4:56}
>>> d2={23:"a", 76:"b", 56:"c"}
>>> result = dict([(d1k,d2[d1v]) for (d1k, d1v) in d1.items()])
>>> result
{1: 'a', 2
[EMAIL PROTECTED] wrote:
> Let's say I have two dictionaries:
> dict1 is 1:23, 2:76, 4:56
> dict2 is 23:A, 76:B, 56:C
>
> How do I get a dictionary that is
> 1:A, 2:B, 4:C
>
>>> dict1 = {1:23, 2:76, 4:56}
>>> dict2 = {23:'A', 76:'B', 56:'C'}
>>> dict((key, dict2[value]) for key, val
[EMAIL PROTECTED] wrote:
> Let's say I have two dictionaries:
> dict1 is 1:23, 2:76, 4:56
> dict2 is 23:A, 76:B, 56:C
>
> How do I get a dictionary that is
> 1:A, 2:B, 4:C
>
>>> dict1 = {1:23,2:76,4:56}
>>> dict2 = {23:'A',76:'B',56:'C'}
>>> dict((k, dict2[v]) for k, v in dict1.items())
{
Let's say I have two dictionaries:
dict1 is 1:23, 2:76, 4:56
dict2 is 23:A, 76:B, 56:C
How do I get a dictionary that is
1:A, 2:B, 4:C
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