Às 01:35 de 06/04/19, Pablo Lucena escreveu:
> Have you looked into eBPF?
I'll take a look at that. Thanks Pablo.
--
https://mail.python.org/mailman/listinfo/python-list
Have you looked into eBPF? They have mature Python bindings. It makes
interacting with the kernel as efficient as possible - you can run it in
production at high resolutions without putting things at risk. One of the
benefits - any averaging / aggregation / histograms / etc can be done by
the kerne
Às 22:18 de 28/03/19, Cameron Simpson escreveu:
> On 28Mar2019 01:12, Paulo da Silva wrote:
>> Às 23:09 de 27/03/19, Cameron Simpson escreveu:
...
>
> Oh, just tangential to this.
>
> If you were doing this ad hoc, yes calling the filefrag executable is
> very expensive. But if you are always d
On 28Mar2019 01:12, Paulo da Silva wrote:
Às 23:09 de 27/03/19, Cameron Simpson escreveu:
On 27Mar2019 21:49, Paulo da Silva wrote:
...
The filefrag manual entry says it works by calling one of 2 ioctls. You
can do that from Python with the ioctl() function in the standard fcntl
module. I ha
Às 23:09 de 27/03/19, Cameron Simpson escreveu:
> On 27Mar2019 21:49, Paulo da Silva wrote:
...
> The filefrag manual entry says it works by calling one of 2 ioctls. You
> can do that from Python with the ioctl() function in the standard fcntl
> module. I haven't tried to do this, but the results
On 27Mar2019 21:49, Paulo da Silva wrote:
I don't know if this is the right group to ask ... sorry if it isn't.
Is there a way to get the file extensions of a file in linux, the same
way as "filefrag -e " does?
The purpose is to see if two files are the same file, namely those
copied with the
Hi!
I don't know if this is the right group to ask ... sorry if it isn't.
Is there a way to get the file extensions of a file in linux, the same
way as "filefrag -e " does?
The purpose is to see if two files are the same file, namely those
copied with the --reflink option in btrfs.
A solution f
